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Advocard [28]
3 years ago
7

If the pattern of the first 6 letters in CIRCUSCIRCUSCIRCUS… continues, what is the pattern’s 500 letter?

Mathematics
2 answers:
tangare [24]3 years ago
8 0

Answer:

I (capital i).

Step-by-step explanation:

We have the pattern:

CIRCUSCIRCUSCIRCUS...

The word "CIRCUS" repeats indefinitely.

And we want to find the 500th letter.

Note that CIRCUS repeats after every 6th letter. So, it will repeat and go back to C after 6 letters, 12 letters, 18 letters, and so on...

Note that 500 is the same as:

500=83(6)+2

So, 500 letters will be the word CIRCUS repeated 83 times plus 2 extra letters.

So the first 83 iterations won't matter as it'll just repeat. We only need to focus on the remaining letters.

After 500 letters, we will have reiterated CIRCUS 83 times for a total of 498 letters and we will start back at C at the 499th letter.

So, our 500th letter will be the letter after (the first) C, or I.

Our 500th letter is I (capital i).  

And we're done!

UkoKoshka [18]3 years ago
8 0

Answer:

I have to agree to the point with this other person

Step-by-step explanation:

The letter would be I (i)

for the exact reason they gave

couldn't have explained it better.

You should mark that person brainliest. I know i would.

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The measure of one angle of a right angle is 50 more then the measure of the smallest angle
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70° and 20°

Step-by-step explanation:

let x be the measure of one angle then x + 50 is the measure of the other angle, thus

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I DONT KNOW THESE! HELP!
kkurt [141]

Answer:

20. x = 5, y = -2

21. x = 11, y = 12

22. x = 22, y = 11

23. x = 11, y = 10

Step-by-step explanation:

20. Opposite sides in the parallelogram are congruent, so

2y+18=3x-1\\ \\6x-3=17-5y

Solve this system of two equations:

\left\{\begin{array}{l}2y-3x=-19\\ \\6x+5y=20\end{array}\right.

Multiply the first equation by 2 and add two equations:

2(2y-3x)+6x+5y=2\cdot (-19)+20\\ \\4y-6x+6x+5y=-38+20\\ \\9y=-18\\ \\y=-2

Substitute it into the first equation:

2\cdot (-2)-3x=-19\\ \\-3x=-19+4\\ \\-3x=-15\\ \\x=5

21. Opposite angles in the parallelogram are congruent, so

11x+5=10y+6

Consecutive angles are supplementary, so

6x-y+11x+5=180^{\circ}

Solve this system of two equations:

\left\{\begin{array}{l}11x-10y=1\\ \\17x-y=175\end{array}\right.

From the second equation

y=17x-175

Substitute it into the first equation:

11x-10(17x-175)=1\\ \\11x-170x+1750=1\\ \\-159x=-1749\\ \\x=11\\ \\y=17\cdot 11-175=187-175=12

22. Opposite angles in the parallelogram are congruent, so

2x-5=3y-12

Consecutive angles are supplementary, so

2x-5+7y+x=180^{\circ}

Solve this system of two equations:

\left\{\begin{array}{l}2x-3y=-7\\ \\3x+7y=185\end{array}\right.

From the first equation

x=-3.5+1.5y

Substitute it into the second equation:

3(-3.5+1.5y)+7y=185\\ \\-10.5+4.5y+7y=185\\ \\-105+45y+70y=1,850\\ \\115y=1,850+105\\ \\115y=1,955\\ \\y=17\\ \\x=-3.5+1.5\cdot 17=22

23. Opposite sides in the parallelogram are congruent, so

2x+9=4y-9\\ \\3x-5=2y+8

Solve this system of two equations:

\left\{\begin{array}{l}2x-4y=-18\\ \\3x-2y=13\end{array}\right.

Multiply the second equation by 2 and subtract it from the first equation:

2x-4y-2(3x-2y)=-18-2\cdot 13\\ \\2x-4y-6x+4y=-18-26\\ \\-4x=-44\\ \\x=11

Substitute it into the first equation:

2\cdot 11-4y=-18\\ \\-4y=-18-22\\ \\-4y=-40\\ \\y=10

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