Those wind chill formulas are REALLY complex.
Attached are the formulas for wind chill (F and C) plus the OLD wind chill formula.
Here's a wind chill calculator I wrote. http://www.1728.org/windchil.htm
(I figured you might need all the help you can get.)
The required expression is 100 - 0.2w
Step-by-step explanation:
Given,
Amount of radioactive substance = 100 mg
The substance decreases by 20% each week.
To find the remaining amount of the in w weeks.
Now,
Each week 20% = 0.2 of the substance will be decreased.
So, in w weeks 0.2×w of the the substance will be decreased.
Hence,
The remaining substance = 100 - 0.2w
Answer:
1,539
Step-by-step explanation:
Using Simple Random Sampling in an infinite population (this is such a large population that we do not know the exact number) we have that the sample size should be the nearest integer to
where
<em>Z= the z-score corresponding to the confidence level, in this case 90%, so Z=1.645 (this means that the area under the Normal N(0,1) between [-1.645,1.645] is 90%=0.9)
</em>
<em>p= the proportion of young urban people (ages 21 to 35 years) who go to at least 3 concerts a year= 35% = 0.35
</em>
<em>q = 1-p = 0.65
</em>
<em>e = the error proportion = 2% = 0.02
</em>
Making the calculations
So, the sample size should be 1,539 young urban people (ages 21 to 35 years)
Step-by-step explanation:
We can rearrange line M so it is in y = mx + b form.
2y - 10x + 3 = 0 -> 2y = 10x - 3 -> y = 5x -3/2. Since line L and line M have the same slope (which is the m value, 5), they are parallel.
I hope this helps! :)
Answer:
5^5
Step-by-step explanation:
He has 5 choices day 1
5 choices day 2
5 choices day 3
5 choices day 4
5 choices day 5
5*5*5*5*5 = 5 ^5
