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myrzilka [38]
3 years ago
14

What is the area of a rectangle that is 27 feet in length and perimeter 116

Mathematics
1 answer:
anygoal [31]3 years ago
7 0
Answer: 837 feet

Explanation:
A rectangle has 4 sides, and you know that 1 side is 27 and another side is 27 because that’s the length.
Subtract 116 - 27 - 27 = 62, which gets you the width. So, the sides of the rectangle are 27 feet, 27 feet, 31 feet, and 31 feet.
Now, to find the area, you multiply length times width. 27•31 = 837.

Hope this helped!
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Jeremy is packaging a stew containers.There are 8 3/4 cups of stew that need to put into 5 to go containers equally.How many cup
11111nata11111 [884]

Answer:

1 3/4 cups

Step-by-step explanation:

In order to be able to equally divide the stew into 5 containers we need to turn everything into the same format, in this case it would be by multiplying the whole number and the denominator and then adding the numerator like so

(8 * 4) + 3 =  \frac{35}{4}

Now we can divide the numerator by 5 (container) in order to calculate how much stew each container will get.

\frac{35}{4} / 5 = \frac{7}{4}

So each container will get 7/4 of the Stew or 1 3/4 cups

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3 years ago
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I think I know this much so far for A (but I could be wrong):
Eduardwww [97]
Part A. You have the correct first and second derivative.

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Part B. You'll need to be more specific. What I would do is show how the quantity (-2x+1)^4 is always nonnegative. This is because x^4 = (x^2)^2 is always nonnegative. So (-2x+1)^4 >= 0. The coefficient -10a is either positive or negative depending on the value of 'a'. If a > 0, then -10a is negative. Making h ' (x) negative. So in this case, h(x) is monotonically decreasing always. On the flip side, if a < 0, then h ' (x) is monotonically increasing as h ' (x) is positive.

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Part C. What this is saying is basically "if we change 'a' and/or 'b', then the extrema will NOT change". So is that the case? Let's find out

To find the relative extrema, aka local extrema, we plug in h ' (x) = 0
h  ' (x) = -10a(-2x+1)^4
0 = -10a(-2x+1)^4
so either
-10a = 0 or (-2x+1)^4 = 0
The first part is all we care about. Solving for 'a' gets us a = 0. 
But there's a problem. It's clearly stated that 'a' is nonzero. So in any other case, the value of 'a' doesn't lead to altering the path in terms of finding the extrema. We'll focus on solving (-2x+1)^4 = 0 for x. Also, the parameter b is nowhere to be found in h ' (x) so that's out as well. 
6 0
3 years ago
115.376 as hundreds tens and ones
Gennadij [26K]

Answer:

NAH FAM- I GOTCHU

RATATATA-

YA LIFE IS A LIE~

JFAIOSDHFAIOSDHFSJD~

FAISDEJHFIAJDE~

WOOOOOOOOOOOOOOOOOOOOOOOOOOO

Step-by-step explanation:

5 0
3 years ago
I will mark brainliest IF CORRECT
umka2103 [35]

Answer:

1 - (π/6) - (√3/4)

Step-by-step explanation:

First, calculate the area of ABCD. That's just 1*1 = 1 un^{2}

Then, we are told that arcs BD and AC are circular, meaning they are portions of a circle. Therefore, let's redraw this image a little. Look below for the image.

Essentially, what I've done is created an equilateral triangle and two sectors. You may be wondering why the triangle is equilateral. Well, we firstly know it's isosceles because the two original arcs are circular and congruent. Their overlap creates two congruent lines that can be extend from point M to the vertices A and D. These two lines also happen to be radii of the quarter circles because the two sectors have AM AND AD as radii. AM and AD = 1, so AMD is an equilateral triangle.

Draw altitude OD. This is a right angle. Since equilateral triangles are also isosceles triangles, and isosceles triangles have the property of sharing the median to base and altitude to base, we can say that OD = \frac{1}{2} AD = \frac{1}{2}. MD = 1, so this triangle is a 30-60-90 triangle. Why? This is because of the 30º angle converse theorem. The shorter leg is half of the hypotenuse MD, so <OMD is a 30º angle, making <ODM a 60º angle and inevitably <MDC a 30º angle (because <D is a right angle) and <ABM as well because the two sectors are congruent.

Because m<ABM = m<MDC = 30º, these two sectors are 30/360 of the individual circles or 1/12 of the original circles, which have areas of π (because 1^2*π = π). Each is 1/12π, combined they are 1/6π.

The area of the equilateral triangle is √3/8. This is because MO can be calculated, using the 30-60-90 ratios, to be √3/2. (1 * √3/2)/2 = (√3/2)/2 = √3/4; this uses the area of a triangle. Now, time to calculate the shaded area.

The area of the square is 1, the area of the sectors π/6, and the equilateral triangle √3/4. Subtract the equilateral triangle and sectors' areas from the area of the square to be left with the remaining shaded part. 1-(π/6)-(√3/4) is your final answer. To put that a little more cleanly below in the image.

Hope this helps, have a great day.

3 0
2 years ago
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J.

x represents the minutes and y shows how many gallons over that time.

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2 years ago
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