A photo is printed on an 11-inch by 13-inch piece of paper. The photo covers 80 square inches and has a uniform border. What is
the width of the border?
2 answers:
Let
w--------> <span>width of the border
we know that
(11-2w)*(13-2w)=80--------> 11*13-22w-26w+4w</span>²=80
143-48w+4w²-80=0
4w²-48w +63=0
using a graph tool------> to resolve the second order equation
see the attached figure
the solution are
w1=1.5
w2-10.5--------> is not solution
the answer is
the width of the border is w=1.5 in
w--------> <span>width of the border
we know that
(11-2w)*(13-2w)=80--------> 11*13-22w-26w+4w</span>²=80
143-48w+4w²-80=0
4w²-48w +63=0
using a graph tool------> to resolve the second order equation
see the attached figure
the solution are
w1=1.5
w2-10.5--------> is not solution
the answer is
the width of the border is w=1.5 in
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Answer:
SEE THE IMAGE ABOVE FOR ANSWER.
Answer: Missing parts are,
In first blank, ,
In second blank, SAS postulate
In third blank, CPCTC postulate
Step-by-step explanation:
Since, Here D is the mid point on the line segment AC.
And BD is a perpendicular to the line AC.
Therefore, In triangles ADB and CDB ( shown in figure)
AD\cong DC ( By the definition of mid point)
( right angles )
( reflexive)
Thus, By SAS ( side angle side )postulate,
So, by CPCTC( Corresponding parts of congruent triangles are congruent)
Now, By definition of congruent segment,
AB=CB
By definition of equidistant,
B is equally far from both A and C.
