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Marysya12 [62]
3 years ago
8

-8x+32=4(-2-4x)What does X equal ​

Mathematics
1 answer:
marshall27 [118]3 years ago
7 0

Answer:

x = - 5

Step-by-step explanation:

Given

- 8x + 32 = 4(- 2 - 4x) ← distribute parenthesis on right side

- 8x + 32 = - 8 - 16x ( add 16x to both sides )

8x + 32 = - 8 ( subtract 32 from both sides )

8x = - 40 ( divide both sides by 8 )

x = - 5

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Gary is baking pretzels for his sister’s party. Some pretzels will be regular and some pretzels will be whole grain.
9966 [12]

Answer:

The constraints are

x+y\geq 14

2y+x\leq 20

x\geq 0

y\geq 0

Step-by-step explanation:

Let

x-------> the number of dozens of regular pretzels.

y-------> the number of dozens of whole-grain pretzels.

we know that

x+y\geq 14 --------> inequality A

2y+x\leq 20 -------> inequality B

x\geq 0 -------> inequality C  (cannot be a negative number)

y\geq 0 ------> inequality D  (cannot be a negative number)

The solution is the triangular shaded area

see the attached figure

7 0
3 years ago
CAN SOMEONE PLEASE ANSWER MY QUESTION?!
sasho [114]

Answer:

0.02 m/sec

Step-by-step explanation:

26/30=0.89 —> 0.89 min —> 53.4 sec

42/50=0.84 meters

speed=0.84 / 53.4 = 0.015 m/sec = 0.02 m/sec

3 0
3 years ago
MARSVECTORCALC6 3.4.020. My Notes A rectangular box with no top is to have a surface area of 64 m2. Find the dimensions (in m) t
ioda

Answer:

We would have

                                    l =w =\frac{8\sqrt{3}}{3} \\h = \frac{8\sqrt{3}}{6}

where " l " is  length, " w"  is width and "h" is height.

Step-by-step explanation:

Step 1

Remember that

         Surface area for a box with no top = lw+2lh+2wh = 64

where " l " is  length, " w"  is width and "h" is height.

 Step 2.

Remember as well that

                              Volume of the box = l*w*h

Step 3

 We can now use lagrange multipliers.  Lets say,

                                    F(l,w,h) = lwh

and

                                g(l,w,h) = lw+2lh+2wh = 64

By the lagrange multipliers method we know that                            

 

                                                     \nabla F  = \lambda \nabla g

Step 4

Remember that

                          \nabla F  = (wh,lh,lw)

and

                      \nabla g = (w+2h,l+2h , 2w+2l)

So basically you will have the system of equations

                              wh = \lambda (w+2h)\\lh = \lambda (l+2h)\\lw = \lambda (2w+2l)

Now, remember that you can multiply the first eqation, by "l" the second equation by "w" and the third one by "h" and you would get

                                   lwh = l\lambda (w+2h)\\\\lwh = w\lambda (l+2h)\\\\lwh = h\lambda (2w+2l)

Then you would get

                      l\lambda (w+2h) = w\lambda (l+2h) =  h\lambda (2w+2l)

You can get rid of \lambda from these equations and you would get

                         lw+2lh = lw+2wh =  2wh+2lh

And from those equations you would get

                                             l = w =2h

Now remember the original equation

                                    lw+2lh+2wh = 64

If we plug in what we just got, we would have

                                 l^{2} + l^{2} + l^2   =  64 \\3l^{2} = 64 \\l = w = \frac{8\sqrt{3} }{3} \\h = \frac{8\sqrt{3} }{6}

                       

                                                 

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FIND THE AREA OF THE COMPOUND
Ivenika [448]

Answer:

69

Step-by-step explanation:

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3 years ago
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