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Alina [70]
3 years ago
5

A flight averages 460 mph. The return flight averages 500 mph due to tailwind. The total flying time is 4.8 hours how long is ea

ch flight
Mathematics
2 answers:
Nesterboy [21]3 years ago
8 0

 

We know that time is distance over velocity, that is:

time = distance / velocity

t = d / v

 

Now from the given:

d / 460 + d / 500 = 4.8

Now we can find for d:

d = 4.8 / [1/460 + 1/500]

d = 1150 miles

 

So the time of each flight is:

flight = 1150 / 460 = 2.5 hours

<span>return flight = 1150 / 500 = 2.3 hours</span>

DaniilM [7]3 years ago
6 0

Answer:

2.5 hours at 460 mph

2.3 hours at 500 mph

Step-by-step explanation:

Distance is velocity times time

d = v * t

We know that both flights have the same distance, so we can express the information with equations:

d = 460 * t1

d = 500 * t2

Where t1 is the time at 460 mph and t2 is the time at 500 mph. We know that:

t = t1 + t2, then

t2 = t - t1

where:

t is the total time and it is 4.8 hours

Now we only have to substitute in the equation:

<em>460 * t1 = 500 * t2</em>

and we know that t2 = 4.8 - t1; so:

<em>460 * t1 = 500 * (4.8 - t1)</em>

Solving:

<em>460 t1 = 2400 - 500 t1</em>

<em>460 t1 + 500 t1 = 2400</em>

<em>960 t1 = 2400</em>

<em>t1 = 2400/960</em>

t1 = 2.5 hours at 460 mph

<em>t2 = 4.8-2.5</em>

t2 = 2.3 hours at 500 mph

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