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3 years ago

Which of the following options could be the measure of a major arc? 80° 106° 180° 196°

Mathematics

2 answers:

Tema [17]3 years ago

7 0

The measure of a major arc would be more than 180 degrees
so the answer would be 196 degrees

Ratling [72]3 years ago

7 0

Answer:

Step-by-step explanation:

alright lets get started.

Before moving to the solution, we need to first understand what major arc is.

The major arc is an arc of a circle which is equal to or more than 180 °angle.

So, out of four given options, angle 180 and angle 196 both satisfy the definition of major arc as one angle is equal to 180 degree and another angle is more than 180 degree.

So, the answers are 180 and 196. answer

Hope it will help. :)

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4 years ago

Given the inequality below:<br><br> 3x-y>4<br><br> Which is the graph of the solution set?

OLga [1]

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A shaded region below a dashed line (y <3x-4)

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4 years ago

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4 years ago

Read 2 more answers

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

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4 years ago