Domain of (x+8)/(x(x+10))
1 answer:
The domain of this, assuming it's a function, is all real numbers such that x does not equal zero or negative ten.
In interval notation, this is (-∞, -10) U (-10, 0) U (0, <span>∞).
In set builder notation, this is {x | x </span>≠ -10, x <span>≠ 0}.
These inputs are excluded from the domain because they would otherwise allow division by zero. Try plugging in one of the restricted inputs. You'll see that it does not work! On a graph of this </span>function, you will see vertical asymptotes.
In interval notation, this is (-∞, -10) U (-10, 0) U (0, <span>∞).
In set builder notation, this is {x | x </span>≠ -10, x <span>≠ 0}.
These inputs are excluded from the domain because they would otherwise allow division by zero. Try plugging in one of the restricted inputs. You'll see that it does not work! On a graph of this </span>function, you will see vertical asymptotes.
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Circles
Area of Circle is
Total percentage increase in the area of the modified circle is 69%
Explanation:
(a) Given the diameter of the circle be d
Then the radius of the circle = r = d/2
and the area of the circle is given by:
Area(A) =
A =
A =
The area of circle is
(b)
The increase in percentage while changing the dimensions is given by the formula :
Total % increase = a% + b% - (a% * b%)/100
Where ,
a% is the percentage increase in side a
b% is the percentage increase in side b
Let the percentage increase in radius is : a%
Since a% = b%
So the formula is
Total increase % = a% + a% + (a% * a%)/100
Given here the diameter of the circle increases by 30% so a =30
Therefore, putting the value of a in the formula
Total increase % = 30% + 30% + (30% *30%)/100
Total increase % = 60% + 9%
Total increase % =69%
Therefore the total percentage increase in the area of the modified circle is 69%