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hram777 [196]
2 years ago
12

How do you make the "Colorize" feature in GIMP consistent if you cannot connect the different places? Brainliest if you also exp

lain how to "cut out" parts of a colorized image and have the un-colorized version appear then colorize part of that.
Computers and Technology
2 answers:
Semenov [28]2 years ago
7 0

What Bugmenot2 said is correct I think.

Brums [2.3K]2 years ago
6 0

Ah, that's easy. You have to select certain parts by using the Free Select tool. Use colorize. Then select the next part and use colorize, but choose the latest used PRESET color to be consistent.

To cut out parts of the image, duplicate your layer without colorization and colorize the top layer. If you have already colorized, put the duplicate as the top layer and click Base Image on the edit history for your original, which is the bottom layer. Use Free Select then click Scissor Select and press the delete button on your keyboard to remove an area, then switch from top layer to bottom layer and use colorize.

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3 years ago
Read 2 more answers
NumA=2<br> for count range (5,8)<br> numA=numA+count <br> print(numA)
love history [14]

Answer:

for count in range (5,8): numA=numA+count print(numA)

Explanation:

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2 years ago
________is one color shade gradually progressing to another shade of the same color or one color progressing to another color.
posledela

Answer:

Gradient fill

Explanation:

A gradient fill is a visual effect that makes a three dimensional color look by mixing one color shade gradually progressing to another shade of the same color or one color progressing to another color. for example a dark red progressively changing to light red or red progressively changing to blue.

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How can you stay safe on the Internet? Check all that apply.
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Answer:

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Explanation:

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2 years ago
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Write a program that first calls a function to calculate the square roots of all numbers from 1 to 1,000,000 and write them to a
svlad2 [7]

Answer:

The csharp program to compute square roots of numbers and write to a file is as follows.

class Program  

{  

static long max = 1000000;  

static void writeRoots()  

{  

StreamWriter writer1 = new StreamWriter("roots.txt");  

double root;  

for (int n=1; n<=max; n++)  

{  

root = Math.Sqrt(n);  

writer1.WriteLine(root);  

}  

}  

static void Main(string[] args)  

{  

writeRoots();  

}  

}

The program to compute squares of numbers and write to a file is as follows.

class Program  

{  

static long max = 1000000;  

static void writeSquares()  

{  

StreamWriter writer2 = new StreamWriter("squares.txt");  

long root;  

for (int n = 1; n <= max; n++)  

{  

root = n*n;  

writer2.WriteLine(root);  

}  

}  

static void Main(string[] args)  

{  

writeSquares();  

}  

}  

Explanation:

1. An integer variable, max, is declared to hold the maximum value to compute square root and square.

2. Inside writeRoots() method, an object of StreamWriter() class is created which takes the name of the file as parameter.

StreamWriter writer1 = new StreamWriter("roots.txt");

3. Inside a for loop, the square roots of numbers from 1 to the value of variable, max, is computed and written to the file, roots.txt.

4. Similarly, inside the method, writeSquares(), an object of StreamWriter() class is created which takes the name of the file as parameter.

StreamWriter writer2 = new StreamWriter("squares.txt");

5. Inside a for loop, the square of numbers from 1 to the value of the variables, max, is computed and written to the file, squares.txt.

6. Both the methods are declared static.

7. Inside main(), the method writeRoots() and writeSquares() are called in their respective programs.

8. Both the programs are written using csharp in visual studio. The program can be tested for any operation on the numbers.

9. If the file by the given name does not exists, StreamWriter creates a new file having the given name and then writes to the file using WriteLine() method.

10. The csharp language is purely object-oriented language and hence all the code is written inside a class.

3 0
3 years ago
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