The equation to calculate the average rate of change is: y/x
y = f(x2) - f(x1)x = x2 - x1
x1: 1 (The smaller x value. It can be any number)x2: 2 (The larger x value. It also can be any number)f(x1): The value when you plug x1 into the function.f(x2): The value when you plug x2 into the function.
If we know this, the variables for this problem are assuming the function is 10(5.5)^x:
x2: 2x1: 1f(x2): 10(5.5)^(2) = 302.5f(x1): 10(5.5)^(1)= 55
This means:y = 302.5 - 55 = 247.5x = 2 - 1 = 1
Remember: the equation for avg rate of change is y/x
So, our average rate of change for the function on the interval [1,2] is 247.5 (y/x = 247.5/1)
Answer:
Perimeter = 317 m
Step-by-step explanation:
Given track is a composite figure having two semicircles and one rectangle.
Perimeter of the given track = Circumference of two semicircles + 2(length of the rectangle)
Circumference of one semicircle = πr [where 'r' = radius of the semicircle]
= 25π
= 25 × 3.14
= 78.5 m
Length of the rectangle = 80 m
Perimeter of the track = 2(78.5) + 2(80)
= 157 + 160
= 317 m
Therefore, perimeter of the track = 317 m
the first choice has a negative 7 and the second choice has a negative 161 these are both negatives in different places which cause a different reaction
Answer:
4°
Step-by-step explanation:
All the angles in a triangle add together to equal 180°. We know there are three angles of 20° so let's subtract this.
20° × 3 = 60°
180° - 60° = 120°
Now well divide 120° up among the three angles.
120° ÷ 3 = 40°
Now we know the angles are 40° + 20°, but we need to find the value of x, so divide 40° by 10
40° ÷ 10 = 4°
x = 4°
Let the length be x and the width be w
The perimeter will be:
2x+3w=1500
thus
3w=(1500-2x)
w=(1500-2x)/3
w=500-2/3x
The area will be:
A=x*w
A=x(500-2/3x)
A=500x-(2/3)x²
The above is a quadratic equation; thus finding the axis of symmetry we will evaluate for the value of x that will give us maximum area.
Axis of symmetry:
x=-b/(2a)
from our equation:
a=(-2/3) and b=500
thus
x=-500/[2(-2/3)]
x=375
the length will be 375 m
The width will be 250 m