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3 years ago

3/12 divide by 6/12 =

Mathematics

1 answer:

BaLLatris [955]3 years ago

3 0

Hey there,
3 / 12 / 6 / 12 = 1 / 2

You can use a calculator right?

Hope this helps :))

~Top

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Which of the following are factors of x^2+5x+4

soldier1979 [14.2K]

Answer:

(x + 4) and (x + 1)

Step-by-step explanation:

x² + 5x + 4

Consider the factors of the constant term (+ 4) which sum to give the coefficient of the x- term (+ 5)

The factors are 4 and 1 , since

4 × 1 = 4 and 4 + 1 = 5 , then

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2 years ago

Nancy put 80 acorns in her backyard. Then, she made a graph of how many acorns different types of squirrels

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Step-by-step explanation:

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2 years ago

Bianca wrote the steps for her solution to the equation 2.3 + 8(1.3x – 4.75) = 629.9. She left out the description for the last

ryzh [129]

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3 years ago

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Solve each quadratic equation by factoring. <br> Show steps pls<br> 8x^2 - 4x = 2x +9

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3 years ago

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Solve the following equation:

Rama09 [41]

Complete the square.

$z^4 + z^2 - i\sqrt 3 = \left(z^2 + \dfrac12\right)^2 - \dfrac14 - i\sqrt3 = 0$

$\left(z^2 + \dfrac12\right)^2 = \dfrac{1 + 4\sqrt3\,i}4$

Use de Moivre's theorem to compute the square roots of the right side.

$w = \dfrac{1 + 4\sqrt3\,i}4 = \dfrac74 \exp\left(i \tan^{-1}(4\sqrt3)\right)$

$\implies w^{1/2} = \pm \dfrac{\sqrt7}2 \exp\left(\dfrac i2 \tan^{-1}(4\sqrt3)\right) = \pm \dfrac{2+\sqrt3\,i}2$

Now, taking square roots on both sides, we have

$z^2 + \dfrac12 = \pm w^{1/2}$

$z^2 = \dfrac{1+\sqrt3\,i}2 \text{ or } z^2 = -\dfrac{3+\sqrt3\,i}2$

Use de Moivre's theorem again to take square roots on both sides.

$w_1 = \dfrac{1+\sqrt3\,i}2 = \exp\left(i\dfrac\pi3\right)$

$\implies z = {w_1}^{1/2} = \pm \exp\left(i\dfrac\pi6\right) = \boxed{\pm \dfrac{\sqrt3 + i}2}$

$w_2 = -\dfrac{3+\sqrt3\,i}2 = \sqrt3 \, \exp\left(-i \dfrac{5\pi}6\right)$

$\implies z = {w_2}^{1/2} = \boxed{\pm \sqrt[4]{3} \, \exp\left(-i\dfrac{5\pi}{12}\right)}$

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1 year ago