In order to find the<u> roots</u> of the cubic equations by <u>graphing</u> you have to follow those steps
we have
we know that
The <u>roots</u> of the function are the values of x when the value of the function is equal to zero
Using a <u>graphing </u>tool
see the attached figure
The<u> roots</u> are
therefore
the answer is
1st,since this GP is convergent that means the common ratio r <1
2nd, sum of a GP = a₁(1-rⁿ)/(1-r), where a₁ = 1st term and n=number of terms
3rd, for any convergent GP, r<1 and the sum of all terms =a₁/(1-r): Why?
[since r<1 → lim rⁿ when n→∞, =0 in the formula of the 2nd)]
Now let's solve :
a) Sum = a₁(1-r³)/(1-r) = 19 (sum of the first 3 terms)
b) Σ(Sum) = a₁/(1-r) = 27 (sum of all terms of this CONVERGENT GP)
Divide a) by b):
[a₁(1-r³)/(1-r)] / [a₁/(1-r)] = 19 /27 ↔ [a₁(1-r³)/(1-r)] x [(1-r)/a₁]=19/27.
Simplify:
(1-r³) = 19/27
-r³ = 19/27 - 1
r³ = 8/27
r = ∛(8/27)
r = 2/3 and a₁ = 9 (Plug r in the Σ sum)
Hence first term a₁ = 9
and common ration r =2/3
Answer:
i think its a :DDDDDD this helps
If sum of 2 shorter sides > longest side , then a triangle can be formed.
9.) 6 + 8 = 14 > 10; yes
10.) 7 + 8 = 15 > 10; yes
11.) 75 + 25 = 100 = 100; no
12.) 1 + 1 = 2 = 2; no
