Answer:
No, because <em>x</em> has multiple values for <em>y</em>.
Step-by-step explanation:
Any input into a function has to map into exactly one output. The input, <em>x</em>, has multiple values for <em>y</em>. Therefore, it is not a function.
Answer:
shift of 6 units left
Step-by-step explanation:
Given f(x) then f(x + a) is a horizontal translation of f(x)
• If a > 0 then a shift left of a units
• If a < 0 then a shift right of a units
f(x) = 3 | x + 6 | + 9
Represents a horizontal shift of the parent function 6 units left
Answer:
![x^{2} + ( 4x) + (147)](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%20%28%204x%29%20%2B%20%28147%29%20)
Step-by-step explanation:
Here, the given expression is
![x^{2} +3x +3 + (2x+134+15) - (x+5)](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B3x%20%2B3%20%2B%20%282x%2B134%2B15%29%20-%20%28x%2B5%29)
Now, simplifying the brackets, we get
= ![x^{2} +3x +3 + 2x+134+15 - x -5](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B3x%20%2B3%20%2B%202x%2B134%2B15%20-%20x%20-5)
Now, operate on the like terms.
= ![x^{2} + ( 3x + 2x -x) + (134 + 15 + 3 -5)](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%20%28%203x%20%2B%202x%20-x%29%20%2B%20%28134%20%2B%2015%20%2B%203%20-5%29%20)
=![x^{2} + ( 4x) + (147)](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B%20%28%204x%29%20%2B%20%28147%29%20)
Hence, the given expression is simplified to the quadratic equation
Answer:
is this for a test?
Step-by-step explanation:
Answer:
None
Step-by-step explanation:
DONUTS CANNOT BECOME BROWNIES