9514 1404 393
Answer:
(-2, 2)
Step-by-step explanation:
The orthocenter is the intersection of the altitudes. The altitude lines are not difficult to find here. Each is a line through the vertex that is perpendicular to the opposite side.
Side XZ is horizontal, so the altitude to that side is the vertical line through Y. The x-coordinate of Y is -2, so that altitude has equation ...
x = -2
__
Side YZ has a rise/run of -1/1 = -1, so the altitude to that side will be the line through X with a slope of -1/(-1) = 1. In point-slope form, the equation is ...
y -(-1) +(1)(x -(-5))
y = x +4 . . . . . . . . subtract 1 and simplify
The orthocenter is the point that satisfies both these equations. Using the first equation to substitute for x in the second, we have ...
y = (-2) +4 = 2
The orthocenter is (x, y) = (-2, 2).
The square will have area
.. (9 cm)^2 = 81 cm^2.
The two triangles together will have area
.. (9 cm)*(12 cm) = 108 cm^2.
The sum of the areas of those three shapes is
.. 81 cm^2 +108 cm^2 = 189 cm^2
Answer:
3x+4
Step-by-step explanation:
f(x) = - x+4
Substitute in x=-3x
f(-3x)= - (-3x) + 4 = 3x+4
We have that Options That are correct are given as
From the question we are told
Which of the following is true for this image?
a. CD is the perpendicular bisector of AB
b. Neither line segment is a perpendicular bisector.
c. AB is the perpendicular bisector of CD
d. both line segments are perpendicular bisectors.
Generally
- CD is the perpendicular bisector of AB
This is True Because CD Cuts Across AB at angle 90 in the middle
- Neither line segment is a perpendicular bisector.
This is Untrue Because CD Cuts Across AB at angle 90 in the middle
- AB is the perpendicular bisector of CD
This is True Because AB Cuts Across CD at angle 90 in the middle
- Both line segments are perpendicular bisectors.
This is True
For more information on this visit
A comparison of two quantities is called a ratio
