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Nutka1998 [239]
3 years ago
6

PLEASE HELP ME BEGGING U

Mathematics
1 answer:
pogonyaev3 years ago
7 0
Based on the outcomes the shirt and the shorts coming out the same color happens two times among the six. This means that 2/6 can be simplified to 1/3.


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What is the value of -2(5) + 3?
pantera1 [17]
Answer is -7

-2(5)+3
-10+3
-7

Hope it helps
4 0
3 years ago
Read 2 more answers
Determine which answers are solutions of the inequality 2x + 1 > 5
svet-max [94.6K]

Answer:

A and E

Step-by-step explanation:

2x + 1 > 5

So, subtract the 1 from both sides,

2x > 4

x > 2

So anything greater than 2...

7 and 3 are greater than 2.

A and E.

5 0
3 years ago
Could you please look at this question?
MrMuchimi

Answer:

  a. see attached

  b. H(t) = 12 -10cos(πt/10)

  c. H(16) ≈ 8.91 m

Step-by-step explanation:

<h3>a.</h3>

The cosine function has its extreme (positive) value when its argument is 0, so we like to use that function for circular motion problems that have an extreme value at t=0. The midline of the function needs to be adjusted upward from 0 to a value that is 2 m more than the 10 m radius. The amplitude of the function will be the 10 m radius. The period of the function is 20 seconds, so the cosine function will be scaled so that one full period is completed at t=20. That is, the argument of the cosine will be 2π(t/20) = πt/10.

The function describing the height will be ...

  H(t) = 12 -10cos(πt/10)

The graph of it is attached.

__

<h3>b. </h3>

See part a.

__

<h3>c.</h3>

The wheel will reach the top of its travel after 1/2 of its period, or t=10. Then 6 seconds later is t=16.

  H(16) = 12 -10cos(π(16/10) = 12 -10cos(1.6π) ≈ 12 -10(0.309017) ≈ 8.90983

The height of the rider 6 seconds after passing the top will be about 8.91 m.

8 0
3 years ago
•<br> Find the HCF of 308 and 420.
oksano4ka [1.4K]

Answer:

28

Step-by-step explanation:

7 0
3 years ago
What’s 4x+10=12<br> Cmon more free points are you just gonna sit there?
GrogVix [38]

Answer:

x=1/2

Step-by-step explanation:

5 0
3 years ago
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