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zhuklara [117]
3 years ago
15

78 davided by 21 what is the anerw

Mathematics
1 answer:
ira [324]3 years ago
3 0

Answer:

Step-by-step explanation:

3.714285714285714‬

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What is 54 in the ratio 5:11:2
qwelly [4]
5/22 I’m pretty that’s the answer
6 0
3 years ago
3. A survey conducted among a group of 50 students showed that; (APPLYING)
Pani-rosa [81]

Answer:

Step-by-step explanation:

this is a set problem (mathematical set)

30 students played soccer

9 students played cricket and soccer

x students played neither cricket nor soccer

3x students played cricket only.

we can see that in the first set 21 appears and in the middle of the set 9 because it says 30 students played soccer adding x and 3x we have the following formula

30 + x + 3x = 50 where x is equal to 5 then ask us Determine the number of students who played cricket. then the value would be 3x + 9 = (3x5) + 9 = 24

5 0
3 years ago
A ___ is a transformation that changes the size but not the shape of a figure. A dilation can ____ or ____ a figure
Liula [17]

Answer:

1) Dilation

2) enlarge or shrink

Step-by-step explanation:

1) The shape stays the same, but the area and size change based upon the scale factor (k)

2) Dilation can shrink or enlarge something based upon a scale factor

Vote Brainliest!!

8 0
3 years ago
Which function is f(x) equal to f^-1(x)?
Morgarella [4.7K]

Answer:

c. f(x) x+1/x-1

Step-by-step explanation:

To answer this question, we need to check each answer one by one until we find the right one.  

y = (x+6)/(x-6)  

switch x and y  

x = (y+6)/(y-6)  

solve for y  

x(y-6) = y+6  

xy - 6x = y+6  

y(x-1) = 6x+6  

y = (6x+6) /(x-1) = 6(x+1)/(x-1)  

f^-1(x) = 6(x+1)/(x-1)  

y = (x+2)/(x-2)  

switch x and y  

x = (y+2)/(y-2)  

solve for y  

x(y-2) = y+2  

xy -2x = y+2  

y(x-1) = 2x+2  

y = (2x+2)/(x-1)  

f^-1(x) = 2(x+1)/(x-1)  

y = (x+1)/(x-1) ------ correct one  

switch x and y  

x = (y+1)/(y-1)  

solve for y  

x(y-1) = y+1  

xy - x = y+1  

y(x-1) = x+1  

y = (x+1)/(x-1)  

f^-1(x) = (x+1)/(x-1)  

f(x) = f^-1(x)

6 0
3 years ago
Read 2 more answers
What is the perimeter of a square which has the same area as a circle with circumfrence of 4π
Kruka [31]

Answer:

Perimeter square = 8 sqrt(pi)

Step-by-step explanation:

The perimeter of a square is 4*s

The area of a circle is Area = pi * r^2

The circumference of a circle is C = 2*pi * r

C = 4 pi

4pi = 2*pi * r

r = 2

So the area of the circle is pi * r^2 = pi * 2^2 = 4pi

The square has the same area

Area = 4*pi

Square = 4*pi

s^2 = 4*pi

s = sqrt(4*pi)

s = 2*sqrt(pi)

The perimeter = 4 * 2 * sqrt(pi)

The perimeter = 8 * sqrt(pi)

8 0
3 years ago
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