Answer:
-3 ≤ x <-2
Step-by-step explanation:
First, you should set up the equation to solve it, which is,
21 ≤ -3(x-4)<18
Then you should simplify the equation to,
21 ≤ -3x+12<18
Then subtract 12 from both sides.
9 ≤ -3x<6
Lastly, divide -3 from both sides.
-3 ≤ x<-2
Answer:
C
Step-by-step explanation:
Let's simplify step-by-step.<span><span><span>6x</span>−<span>9x</span></span>−5</span><span>=<span><span><span><span><span>6x</span>+</span>−<span>9x</span></span>+</span>−5</span></span>Combine Like Terms:<span>=<span><span><span>6x</span>+<span>−<span>9x</span></span></span>+<span>−5</span></span></span><span>=<span><span>(<span><span>6x</span>+<span>−<span>9x</span></span></span>)</span>+<span>(<span>−5</span>)</span></span></span><span>=<span><span>−<span>3x</span></span>+<span>−5</span></span></span>Answer:<span>=<span><span>−<span>3x</span></span>−<span>5</span></span></span>
Round pan volume is:
3.14•r^2•h
D=7 so r=3.5 in
3.14• (3.5^2)•2 = 76.97 in^3
Rec. pan vol. is :
9•6•2= 108 in^3
Rec. Pan is larger because 108 in^3 is > 76.97 in^3 :) .
The icing that will be needed to frost the round cake pan is:
We need to find the surface area:
S.A= 3.14r^2 + 2 • 3.14•r • h .... 3.14 is the value of PI
So, S.A= 3.14• 3.5^2 + 6.28• 3.5• 2= 82.47 in^2 the icing that'll be needed to frost the round cake pan.
Icing that will be needed for the rec. cake pan is:
2•9•2=36 in^2
6•9•2= 108in^2
6•2= 12 in^2
S.A= 156 in^2 the icing needed to frost the rec. cake pan .... the S.A of all sides except the bottom one :).
Good luck ;-)
