What is the question so I can help there no tiles showe
I found this!!!!
The scientist can use these two measurements to calculate the distance between the Sun and the shooting star by applying one of the trigonometric functions: Cosine of an angle.
- The scientist can substitute these measurements into cos\alpha=\frac{adjacent}{hypotenuse}cosα=
hypotenuse
adjacent
and solve for the distance between the Sun and the shooting star (which would be the hypotenuse of the righ triangle).
Step-by-step explanation:
You can observe in the figure attached that "AC" is the distance between the Sun and the shooting star.
Knowing the distance between the Earth and the Sun "y" and the angle x°, the scientist can use only these two measurements to calculate the distance between the Sun and the shooting star by applying one of the trigonometric functions: Cosine of an angle.
This is:
cos\alpha=\frac{adjacent}{hypotenuse}cosα=
hypotenuse
adjacent
In this case:
\begin{gathered}\alpha=x\°\\\\adjacent=BC=y\\\\hypotenuse=AC\end{gathered}
α=x\°
adjacent=BC=y
hypotenuse=AC
Therefore, the scientist can substitute these measurements into cos\alpha=\frac{adjacent}{hypotenuse}cosα=
hypotenuse
adjacent
, and solve for the distance between the Sun and the shooting star "AC":
cos(x\°)=\frac{y}{AC}cos(x\°)=
AC
y
AC=\frac{y}{cos(x\°)}AC=
cos(x\°)
y
Answer:
60 times will they ring together at the same second in one hour excluding the one at the end.
Step-by-step explanation:
Given : Five bells begin to ring together and they ring at intervals of 3, 6, 10, 12 and 15 seconds, respectively.
To find : How many times will they ring together at the same second in one hour excluding the one at the end?
Solution :
First we find the LCM of 3, 6, 10, 12 and 15.
2 | 3 6 10 12 15
2 | 3 3 5 6 15
3 | 3 3 5 3 15
5 | 1 1 5 1 5
| 1 1 1 1 1
So, the bells will ring together after every 60 seconds i.e. 1 minutes.
i.e. in 1 minute they rand together 1 time.
We know, 1 hour = 60 minutes
So, in 60 minute they rang together 60 times.
Therefore, 60 times will they ring together at the same second in one hour excluding the one at the end.
The number is 79 that is prime
