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3 years ago

5

A stock on the New York Stock Exchange opened at $52 on Monday morning. The table shows the change in the value of the stock for

each day that week. What was the stock worth at the close of business on Friday?

1 answer:

Leni [432]3 years ago

7 0

Answer:

New york

Step-by-step explanation:

Energy. There's no other city on the planet with an energy that can compete with New York. The fast pace, the buzzing traffic, the hustle and bustle of the people, the 24-hour life, and the creative spirit make NYC one of the most vibrant places in the world.rent people than we were 365 days ago.

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Mr Webster is buying carpet for an exercise room in his basement the room will have an art of 230 square feet the width of the r

abruzzese [7]

230/1 times 12 1/2 on a fraction calculator should give you the answer :)

3 0

3 years ago

Please could you find the answers to the questions in the attachment.

Fudgin [204]

( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
1. midpoint equation which is ( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ ) when you have 2 points

2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height

so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=( $\frac{11+19}{2} , \frac{10+6}{2}$ )
midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
midpoint= (15,8)

point x=(15,8)

y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=( $\frac{5+21}{2} , \frac{8+0}{2}$ )
midpoint=( $\frac{26}{2} , \frac{8}{2}$ )
midpoint=(13,4)

Y=(13,4)

legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= $\sqrt{(19-11)^{2}+(6-10)^{2}}$
D= $\sqrt{(8)^{2}+(-4)^{2}}$
D= $\sqrt{64+16}$
D= $\sqrt{80}$
D= $4 \sqrt{5}$
BC= $4 \sqrt{5}$

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= $\sqrt{(13-15)^{2}+(4-8)^{2}}$
D= $\sqrt{(-2)^{2}+(-4)^{2}}$
D= $\sqrt{4+16}$
D= $\sqrt{20}$
D= $2 \sqrt{5}$
XY= $2 \sqrt{5}$

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC= $4 \sqrt{5}$ and XY= $2 \sqrt{5}$

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= $\sqrt{(21-5)^{2}+(0-8)^{2}}$
D= $\sqrt{(16)^{2}+(-8)^{2}}$
D= $\sqrt{256+64}$
D= $\sqrt{320}$
D= $4 \sqrt{2}$
AD= $4 \sqrt{2}$

so we have
AD= $4 \sqrt{2}$
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
( $4 \sqrt{2}+4 \sqrt{5}$ ) times 1/2 times $2 \sqrt{5}$ =
( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
$4 \sqrt{10}+4*5$ = $4 \sqrt{10}+20$ =80 $\sqrt{10}$ =252.982

X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
Area=80 $\sqrt{10}$ square unit or 252.982 square units

7 0

3 years ago

The sum of five times a number and -6 is -2

koban [17]

So,

"The sum of five times a number and -6"
5n + -6 or 5n - 6

"is -2"
= -2

5n - 6 = -2

Add 6 to both sides.
5n = 4

Divide both sides by 5.
$n = \frac{4}{5} \ or\ 0.8\ or\ 80\ percent$

7 0

3 years ago

ANSWER PLZ ASAP!!!!!!!!!!!!!!

hammer [34]

Just substitute r with 357 and solve.

= 1/7(357) + 3(1/7(357))

= 51 + 3(51)

= 51 + 153

= 204

Therefore, Eliza read 204 in those 3 days.

Best of Luck!

7 0

3 years ago

Read 2 more answers

I need help please #19

o-na [289]

Answer:

40

Step-by-step explanation:

5 0

3 years ago