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White raven [17]
3 years ago
9

Solve for h. −110=13+3(4h−6)

Mathematics
1 answer:
givi [52]3 years ago
4 0
-35/4 should be the answer.

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pashok25 [27]
The answer is B becuase if u take the reciplericle by the antiretroviral you would get B
3 0
2 years ago
Which of the following expressions is this one equivalent to?
Alborosie
We know that 
the euclid's division A/B implies A= BQ + R
wher Q = the quotient, and R is the remainder
<span>after doing euclid's division, (3x^3+15x^2+17x+3)/x+5 = 3x²+17and R= - 82
so </span>(3x^3+15x^2+17x+3= (3x²+17) (x+5) -82

the answer is x^3+15x^2+17x+3= (3x²+17) (x+5) - 82
8 0
3 years ago
Read 2 more answers
Which of the following is equivalent to (4 x 10^-7) + (5 x 10^-7)
Vera_Pavlovna [14]
The correct answer is D
3 0
2 years ago
100 POINTS WILL GIVE BRAINLIEST TO RIGHT ANSWER
OLEGan [10]

Answer: I think R2. is reflexive property (?)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Use a(t) = −9.8 meters per second per second as the acceleration due to gravity. (Neglect air resistance.) A canyon is 2100 mete
Umnica [9.8K]

Answer:

t \approx 20.7\,s

Step-by-step explanation:

Given that rock experiments a constant acceleration, position function can be obtained by integrating twice:

v(t) = v_{o} - a\cdot t

s(t) = s_{o} + v_{o}\cdot t -\frac{a}{2}\cdot t^{2}

The initial conditions of the rock are, respectively:

s_{o} = 2100\,m

v_{o} = 0\,\frac{m}{s}

Position of the rock as a function of time is:

s(t) = 2100\,m -(4.9\,\frac{m}{s^{2}})\cdot t^{2}

The time taken for the rock to hit the canyon floor is:

0\,m = 2100\,m - (4.9\,\frac{m}{s^{2}} )\cdot t^{2}

2100\,m = (4.9\,\frac{m}{s^{2}} )\cdot t^{2}

t = \sqrt{\frac{2100\,m}{4.9\,\frac{m}{s^{2}} } }

t \approx 20.7\,s

8 0
3 years ago
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