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cupoosta [38]
3 years ago
8

Which of the following expressions is this one equivalent to?

Mathematics
2 answers:
Alborosie3 years ago
8 0
We know that 
the euclid's division A/B implies A= BQ + R
wher Q = the quotient, and R is the remainder
<span>after doing euclid's division, (3x^3+15x^2+17x+3)/x+5 = 3x²+17and R= - 82
so </span>(3x^3+15x^2+17x+3= (3x²+17) (x+5) -82

the answer is x^3+15x^2+17x+3= (3x²+17) (x+5) - 82
arsen [322]3 years ago
3 0

Answer:

option (c) is correct,

3x^2+17-\frac{82}{x+5} is the equivalent fraction to the given expression \frac{3x^3+15x^2+17x+3}{x+5}

Step-by-step explanation:

Given expression ,  \frac{3x^3+15x^2+17x+3}{x+5}

We have to choose an equivalent fraction from the given options.

Consider expression (c) ,

3x^2+17-\frac{82}{x+5}

Taking LCM , Multiply 3x^2+17 by (x+5) , we get,

\frac{3x^2(x+5)+17(x+5)-82}{x+5}

On solving , we get,

\frac{3x^3+15x^2+17x+85-82}{x+5}

On simplifying, we get,

\frac{3x^3+15x^2+17x+3}{x+5}

Which is equal to the given expression.

Thus, option (c) is correct,

3x^2+17-\frac{82}{x+5} is the equivalent fraction to the given expression \frac{3x^3+15x^2+17x+3}{x+5}

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2 years ago
Combine like terms.<br> 3y + y + 6y<br> A. 10y<br> B. 8y<br> C. 9y-y<br> D. 2y
a_sh-v [17]

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Step-by-step explanation:


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Step-by-step explanation:

8 0
2 years ago
In how many ways can a
Tomtit [17]

Answer:

The answer is 364. There are 364 ways of choosing a recorder, a facilitator and a questioner froma club containing 14 members.

This is a Combination problem.  

Combination is a branch of mathematics that deals with the problem relating to the number of iterations which allows one to select a sample of elements which we can term "<em>r</em>" from a collection or a group of distinct objects which we can name "<em>n</em>". The rules here are that replacements are not allowed and sample elements may be chosen in any order.

Step-by-step explanation:

Step I

The formula is given as

C (n,r) = \frac{n}{r} = \frac{n!}{(r!(n-r)!)}

n (objects) = 14

r (sample) = 3

Step 2 - Insert Figures

C (14, 3) = (\frac{14}{3}) = \frac{14!}{(3!(14-3)!)}

= \frac{87178291200}{(6 X 39916800)}

= \frac{87178291200}{239500800}

= 364

Step 3

The total number of ways a recorder, a facilitator and a questioner can be chosen in a club containing 14 members therefore is 364.

Cheers!

6 0
3 years ago
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