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cupoosta [38]
4 years ago
8

Which of the following expressions is this one equivalent to?

Mathematics
2 answers:
Alborosie4 years ago
8 0
We know that 
the euclid's division A/B implies A= BQ + R
wher Q = the quotient, and R is the remainder
<span>after doing euclid's division, (3x^3+15x^2+17x+3)/x+5 = 3x²+17and R= - 82
so </span>(3x^3+15x^2+17x+3= (3x²+17) (x+5) -82

the answer is x^3+15x^2+17x+3= (3x²+17) (x+5) - 82
arsen [322]4 years ago
3 0

Answer:

option (c) is correct,

3x^2+17-\frac{82}{x+5} is the equivalent fraction to the given expression \frac{3x^3+15x^2+17x+3}{x+5}

Step-by-step explanation:

Given expression ,  \frac{3x^3+15x^2+17x+3}{x+5}

We have to choose an equivalent fraction from the given options.

Consider expression (c) ,

3x^2+17-\frac{82}{x+5}

Taking LCM , Multiply 3x^2+17 by (x+5) , we get,

\frac{3x^2(x+5)+17(x+5)-82}{x+5}

On solving , we get,

\frac{3x^3+15x^2+17x+85-82}{x+5}

On simplifying, we get,

\frac{3x^3+15x^2+17x+3}{x+5}

Which is equal to the given expression.

Thus, option (c) is correct,

3x^2+17-\frac{82}{x+5} is the equivalent fraction to the given expression \frac{3x^3+15x^2+17x+3}{x+5}

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How fast the volume of the sphere is changing when the surface area is 10 square centimeters is it is increasing at a rate of 30 cm³/s.

To solve the question, we need to know the volume of a sphere

<h3>Volume of a sphere</h3>

The volume of a sphere V = 4πr³/3 where r = radius of sphere.

<h3>How fast the volume of the sphere is changing</h3>

To find the how fast the volume of the sphere is changing, we find rate of change of volume of the sphere. Thus, we differentiate its volume with respect to time.

So, dV/dt = d(4πr³/3)/dt

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Learn more about how fast volume of sphere is changing here:

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Answer:

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Step-by-step explanation:

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