A line segment has (three one two zero) endpoints
The answer is 2
Answer:
Given a triangle ABC, Pythagoras' Theorem shows that:
Thus,
The distance formula, gives an equivalent expression based on two points at the end of the hypotenuse for a triangle.
Therefore when given the hypotenuse with endpoints at
We know that the third point of the right triangle will be at
and that the two side lengths will be defined by the absolute values of:
Answer:
97
Step-by-step explanation:
bc
Answer:
<h2>P(x) = (x+3)(x-2)^2</h2>
Step-by-step explanation:
Looking at the brackets you can see where the curve will intersect the x-axis.
The graph shows the curve intersecting at (0,-3) and (0,2).
This means:
x = -3
AND
x = 2
Rearrange the equations, equating them to 0.
x + 3 = 0
x - 2 = 0
This will be the values in the brackets.
Because the curve only touches 0,2 and DOES NOT cross it, we know that x - 2 is a repeated root, hence (x-2) is squared.
Therefore your brackets are: (x+3)(x-2)(x-2)
Which can be simplified:
(x+3)(x-2)^2
Where ^2 means squared.
Answer: n = 4
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