Answer: A) 0.0394 kg · m2/s
The angular momentum is equal to M = 0.0394kgm^2/s
Explanation:
Given;
Mass of stick = 135g = 0.135kg
Length L = 1m
Angular speed w = 3.50 rad/s
The angular momentum is given as;
M = I×w
Where I = moment of inertia
In this case I is given as;
I = 1/12(m×L^2)
I = 1/12( 0.135 × 1^2)
I = 0.01125kgm^2
The angular momentum can then be calculated as
M = 0.01125kgm^2×3.50rads/s
M = 0.039375kgm^2/s
M = 0.0394kgm^2/s
The angular momentum is equal to M = 0.0394kgm^2/s
Answer:
Explanation:
C = 6 x 10^-6 F, V = 12 V,
Energy stored in the capacitor
E = 1/2 CV^2 = 0.5 x 6 x 10^-6 x 12 x 12 = 4.32 x 10^-4 J
Now the voltage is 6 V, So let energy be E'
E' = 1/2 CV^2 = 0.5 x 6 x 10^-6 x 6 x 6 = 1.08 x 10^-4 J
The energy stored in a capacitor is proportional to the square of teh potential difference applied across the capacitor.
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Answer:
Work done, W = 255.21 J
Explanation:
It is given that,
Rotational inertia of the wheel,
Angular displacement,
Initial angular velocity,
Final angular velocity,
Firstly finding the angular acceleration of the wheel using the equation of rotational kinematics as :
Work done by the torque is given by :
W = 255.21 J
Out of given options, the correct option for the work done by the torque is 255.21 J. Hence, this is the required solution.