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3 years ago

What are ten different uses for solar energy?

Physics

1 answer:

Yuki888 [10]3 years ago

8 0

Answer:

Top 10 Residential Uses for Solar Energy.

01. Solar Powered Ventilation Fans.

02. Solar Heating for Your Swimming Pool.

03. Solar Water Heater.

04. Solar House Heating.

05.Solar Powered Pumps.

06. Charging Batteries With Solar Power.

07. Power Your Home With Photo-Electric.

08. Solar Energy For Cooking.

09. Solar energy for outdoor lighting.

10. Solar transportation.

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Dr. Eriksson is working on a material called selenium. She is adding a certain number and type of atoms to the selenium, which w

Katarina [22]

Answer:

Selenium is a semiconductor

Explanation:

Selenium is a semiconductor.

Elements in the column IV and VI of the periodic table are referred to as Semiconductor.

Selenium lies in the column VI along with Tellurium

Some other elements of the column IV are silicon, germanium, and tin

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3 years ago

Read 2 more answers

A 1500 kg car traveling at 15.0 m/s to the south collides with a 4500 kg truck that is at rest at a stopligt. The car comes to a

Arlecino [84]

Answer:

Mathematically:

That will be

= 1500 x 15 x 4500

= 101,250,000

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2 years ago

Calculate the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s.

Aleonysh [2.5K]

De broglie wavelength, $\lambda = \frac{h}{mv}$ , where h is the Planck's constant, m is the mass and v is the velocity.

$h = 6.63*10^{-34}$

Mass of hydrogen atom, $m = 1.67*10^{-27}kg$

v = 440 m/s

Substituting

Wavelength $\lambda = \frac{h}{mv} = \frac{6.63*10^{-34}}{1.67*10^{-27}*440} = 0.902 *10^{-9}m = 902 *10^{-12}m$

$1 pm = 10^{-12}m\\ \\ So , \lambda =902 pm$

So the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s is 902 pm

7 0

3 years ago

To practice Tactics Box 9.1 Calculating the Work Done by a Constant Force. Recall that the work W done by a constant force F⃗ at

insens350 [35]

Answer:

The vector magnitudes F and r are always postive, so the sign o W is determined entirely by the angle e between the force and the displacement.Submit Figure 1 off 1 part C

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3 years ago

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1. 1500j of work was done to move a box 20m. What force was applied to the box ?

Fantom [35]

Answer:

1. 75N

2. 67,983 J (=67.98 kJ)

Explanation:

1. Work = Force x Distance

we are given that Work = 1,500J and Distance = 20m

hence,

Work = Force x Distance

1,500 = Force x 20

Force = 1,500 ÷ 20 = 75N

2. Potential Energy, PE = mass x gravity x change in height

we are given that mass = 165 kg and change in height = 42m

assuming that gravity, g = 9.81 m/s²

Potential Energy, PE = mass x gravity x change in height

Potential Energy, PE = 165 x 9.81 x 42 = 67,983 J (=67.98 kJ)

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3 years ago