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ArbitrLikvidat [17]
3 years ago
12

The​ temperature, T, in degrees​ Fahrenheit, in a​ car's radiator during the first 4 minutes of driving is a function of​ time,

t. The temperature can be found by the formula Upper T equals 5.8 t squared plus 14 t plus 32​, 0less than or equalstless than or equals4. ​a) What is the car​ radiator's temperature at the instant the car is turned​ on? ​b) What is the car​ radiator's temperature after the car has been driven for 2 minutes​? ​c) How long after the car has begun operating will the car​ radiator's temperature reach 80degrees​F?
Mathematics
1 answer:
devlian [24]3 years ago
3 0

Answer:

Step-by-step explanation:

T = 5.8t² + 14t + 32 ( 0 ≤ t ≤4 )

a ) when t = 0 ( when car is turned on )

T = 32 ° F .

b ) When t = 2

T = 5.8t² + 14t + 32

= 5.8 x 2² + 14 x 2 + 32

= 23.2 + 28 + 32

= 83.2 ° F

c )

T = 80 ;  to find t = ?

80 = 5.8t² + 14t + 32

5.8t² + 14 t - 48 = 0

t = \frac{-14+/-(14^2-4\times 5.8\times -48)^\frac{1}{2} }{2\times 5.8}

t = 1.9 minutes  . approx .

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7 0
3 years ago
Please answer quickly<br>expand and simplify: 4(5x-3y) (x-4y) -(3x-4y)(2x+3y)​
Gekata [30.6K]

Answer: 14x^2-93xy+60y^2 Hope that helps!

Step-by-step explanation:

1. Expand by distributing terms

(20x-12y)(x-4y)-(3x-4y)(2x+3y)

2. Use the Foil method:(a+b)(c+d)= ac+ad+bc+bd

20x^2-80xy-12yx+48y^2-(3x-4y)(2x+3y)

3. Use the Foil method : (a+b)(c+d)= ac+ad+bc+bd

20x^2-80xy-12yx+48y^2-(6x^2+9xy-8yx-12y^2)

4. Remove parentheses 20x^2-80xy-12yx+48y^2-6x^2-9xy+ 8yx+12y^2

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6. Simplify.

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5 0
3 years ago
The volume of a rectangular box with a square base remains constant at 500 cm3 as the area of the base increases at a rate of 6
Andre45 [30]

Answer:

the rate at which the height of the box is decreasing is -0.0593 cm/s

Step-by-step explanation:

Given the data in the question;

Constant Volume of a rectangular box with a square base = 500 cm³

area of the base increases at a rate of 6 cm²/sec

so change in the area of the base with respect to time dA/dt = 6 cm²/sec

each side of the base is 15 cm long

so Area of the base = 15 cm × 15 cm = 225 cm²

the rate at which the height of the box is decreasing = ?

Now,

V = Ah

dv/dt = 0 ⇒ Adh/dt + hdA/DT = 0

⇒ dh/dt = -hdA/dt / A

we substitute

dh/dt = [ -( 500 / 225 ) × 6 ] / 225

dh/dt = [ -(2.22222 × 6)  ] / 225

dh/dt = [ -13.3333 ] / 225

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Therefore, the rate at which the height of the box is decreasing is -0.0593 cm/s

7 0
2 years ago
A football player gains 7 yards, loses 4 yards, and gains 12 yards. Write his gains and losses as integers. If
Alexxx [7]
If he started at 0 where does he end up?

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5 0
3 years ago
Read 2 more answers
THIRD TIME ASKING FOR HELP PLEASE HELP ME!!!!!!!!!!!!!!!!!!!
Fed [463]
<h3>Answer:  9 units</h3>

========================================================

Explanation:

For now, focus on triangle ABD. This is a right triangle due to BD being an altitude.

Use the pythagorean theorem to find that...

(AD)^2 + (BD)^2 = (AB)^2

(1)^2 + (BD)^2 = (3)^2

1 + (BD)^2 = 9

(BD)^2 = 9-1

(BD)^2 = 8

Normally we would isolate BD itself, but I'll stop short and use that last line instead.

------------------

The triangles ABD and BCD are similar triangles (we can prove this using the AA similarity theorem).

Since we have similar triangles, we can form the proportion shown below

AD/BD = BD/CD

This cross multiplies to

AD*CD = (BD)^2

We know that AD = 1 and (BD)^2 = 8, so,

AD*CD = (BD)^2

1*CD = 8

CD = 8

This then means,

x = CD+DA

x = 8+1

x = 9

AC is 9 units long.

8 0
2 years ago
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