Since you're only asked the ordered pair of D'', it's much easier just to plot and reflect point D twice than to do that for all four points!
Remember that reflecting points is like putting a mirror at the line of reflection or flipping that point over at that line. The reflected point should be the same distance from the line of reflection as the original point.
1) Reflect D over the x-axis to get D'.
D is at (4,1). Draw a line that is perpendicular to the line of reflection and goes through D. D is as far from the line of reflection as D' should be on its other side (both are on that perpendicular line). Since D is 1 unit above the x-axis, that means D' is 1 unit below at (4, -1). See picture 1.
2) Reflect D' over <span>y=x+1 to get D''.
D' is at (4, -1). Draw </span>y=x+1 and the line perpendicular to it going through D''. D'' is the same distance from the line of reflection on the other side. See picture 2. D'' is at (-2, 5).
Answer: D'' is at (-2, 5)
Answer:
x
=
9
+
√
33
/12
, 9
−
√
33 12
or
x
=
1.22871355
…
, 0.27128644
…
Step-by-step explanation:
angle 1 = 180° - 115° (Linear Pair)
<u>angle 1 = 65°</u>
<u>angle 2 = angle 1 = 65°</u> ( Angles on the equal sides of an isosceles triangle )
angle 3 = 180° - (65° + 65°) (Angle Sum Property)
angle 3 = 180° - 130°
<u>angle</u><u> </u><u>3</u><u> </u><u>=</u><u> </u><u>5</u><u>0</u><u>°</u>
angle 4 = 180° - 65° (Linear Pair)
<u>angle</u><u> </u><u>4</u><u> </u><u>=</u><u> </u><u>1</u><u>1</u><u>5</u><u>°</u>
<u>angle</u><u> </u><u>5</u><u> </u><u>=</u><u> </u><u>1</u><u>1</u><u>5</u><u>°</u> (Vertically Opposite Angles)
Answer:
should have divided it directly ........ maybe or it's just messy........ maybe
Step-by-step explanation:
..........
...........
8x + 16 = 36
8x = 36 - 16
8x = 20
x = 20 / 8
x = 2.5
Answer:
i dont think this is a real equation.
Step-by-step explanation: