Since secant is the inverse of cosine function, when the cosine function has a 'zero' the secant will have a vertical asymptote.
Graphing a cosine with a right shift of pi, the zeros would be at pi and 2pi.
This will make the vertical asymptotes of the secant function be at pi and 2pi.
I hope you understand.
Answer:
Step-by-step explanation:
sina=opposite/hypotenuse=7/25
cosa=adjacent/hypotenuse=24/25
tana=opposite/adjacent=7/24
sinc=opposite/hypotenuse=24/25
cosc=adjacent/hypotenuse=7/25
tanc=opposite/adjacent=24/7
Answer:
Mine is not working as well
Step-by-step explanation:.
Answer:
Step-by-step explanation:
I think 75 dollars
Your answer is A. Megan is correct. When two lines have different slopes, they must intersect, producing one solution.