Answer:
Step-by-step explanation:
The attached photo shows the diagram of quadrilateral QRST with more illustrations.
Line RT divides the quadrilateral into 2 congruent triangles QRT and SRT. The sum of the angles in each triangle is 180 degrees(98 + 50 + 32)
The area of the quadrilateral = 2 × area of triangle QRT = 2 × area of triangle SRT
Using sine rule,
q/SinQ = t/SinT = r/SinR
24/sin98 = QT/sin50
QT = r = sin50 × 24.24 = 18.57
Also
24/sin98 = QR/sin32
QR = t = sin32 × 24.24 = 12.84
Let us find area of triangle QRT
Area of a triangle
= 1/2 abSinC = 1/2 rtSinQ
Area of triangle QRT
= 1/2 × 18.57 × 12.84Sin98
= 118.06
Therefore, area of quadrilateral QRST = 2 × 118.06 = 236.12
The term to term rule is multiplying by 4 and if we continue doing this, we will move towards very large positive numbers.
This sequence, therefore, diverges to infinity
3) 0.825
4) 0.1212
5) 0.5455
6) -7.177
7a) 0.066
b) 0.166
c) 0.333
d) 0.416
8) -2/5
9) -7 (32/100) = -7 (9/25)
10) 0.22222 = 2/9
Check the picture below.
let's recall that a rhombu's sides are all equal.
Answer:
+89
Step-by-step explanation: