Answer:
whatttt!!!!!!!!!!
Step-by-step explanation:
Answer: a. 1.981 < μ < 2.18
b. Yes.
Step-by-step explanation:
A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.
First, we calculate mean of the sample:


2.08
Now, we estimate standard deviation:


s = 0.1564
For t-score, we need to determine degree of freedom and
:
df = 12 - 1
df = 11
= 1 - 0.95
α = 0.05
0.025
Then, t-score is
= 2.201
The interval will be
± 
2.08 ± 
2.08 ± 0.099
The 95% two-sided CI on the mean is 1.981 < μ < 2.18.
B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.
Answer:
The probability that he teleports at least once a day = 
Step-by-step explanation:
Given -
Evan lives in Stormwind City and works as an engineer in the city of ironforge in the morning he has three Transportation options teleport ride a dragon or walk to work and in the evening he has the same three choices for his trip home.
Total no of outcomes = 3
P( He not choose teleport in the morning ) = 
P( He not choose teleport in the evening ) = 
P ( he choose teleports at least once a day ) = 1 - P ( he not choose teleports in a day )
= 1 - P( He not choose teleport in the morning )
P( He not choose teleport in the evening )
= 
= 
The 13 pound bag is 1/2 of the 26 pound bag so if 40 dogs eat that then 20 dogs will eat 13 pounds.
Your answer should be 20 dogs
The mean of those sets of numbers are 17.5