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lys-0071 [83]
3 years ago
6

What does the motif of time represent?

Advanced Placement (AP)
2 answers:
Sauron [17]3 years ago
7 0
The term "motif" refers to recurring ideas or thoughts that act as a unifying idea, and it sometimes develops as a commentary on characterization or on the central ideas in the work. Sometimes motifs recur so frequently that they enhance the meaning of the novel and often rise to symbolic importance.
Brut [27]3 years ago
6 0

Answer: something that changes depending on the situation

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The answer is Separation of Powers
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Qué respuesta daría a las personas que creen que los jóvenes hacen un uso excesivo del celular?
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PLEASE TRANSLET IT IN ENGLISH BECAUSE I CANT UNDERSTAND IT

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Over the past few decades, the average intelligence scores have increased. This phenomena best illustrates why intelligence test
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Answer:

A.

Explanation:

This phenomenon best illustrates why intelligence tests need to be revised for predictive validity. The tests are taken initially and show high scores, then they are taken again and show even higher scores. This shows that the individuals are getting smarter. If the test continues to be taken without revision then the same results will continue since the individuals will continue to become smarter but the test will continue being the same. Therefore, becoming much easier for the participants every time. This ultimately leads to better and better scores.

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3 years ago
Hello, I need help with a calculus FRQ. My teacher has given a hint that this last part has to do with the intermediate value th
lesya [120]

Answer:

Yes, at a time t such that (√2)/2 ≤ t ≤ 2.

Explanation:

To answer the question

Therefore, where the domain of the function is the set of all real numbers x for which f(x) is a real number we have

For Chloe's velocity

C(t) = t\times e^{4-t^2} \ for \ 0\leq t\leq 2

Finding the boundaries of the function gives;

0\times e^{4-0^2} = 0 and 2\times e^{4-2^2} = 2

At t = 1, we have 1\times e^{4-1^2} = e^{3} = 20.086

We find the maximum point as follows;

\frac{\mathrm{d} \left (t\times e^{4-t^2}   \right )}{\mathrm{d} x}=0

From which we have;

\frac{\mathrm{} e^{4-t^2} - t\times e^{4-t^2} \times2\times t }{(e^{4-t^2} )^2}=0

e^{4-t^2} - t\times e^{4-t^2} \times2\times t }=0

e^{4-t^2}(1 - t\times2\times t })=0\\e^{4-t^2}(1 - 2\times t^2 })=0\\

e^{4-t^2}=0 or (1 - 2\times t^2 })=0

∴ 1 = 2·t² and from which t = (√2)/2

Hence the function C(x) is decreasing from t = (√2)/2 to t = 2

For Brandon

For 0 ≤ t ≤ 1, 1 ≤ B(t) ≤8 and for 1 < t ≤ 2, 8 < B(t) ≤ 1.5

1 ≤ f(x) ≤ 1.5

Given that the function B(t) is differentiable, therefore, continuous, there exists a point at which the function C(t) and B(t) intersects given that;

For 0 ≤ t ≤ (√2)/2, 0 ≤ C(t) ≤ 23.416 for (√2)/2 < t ≤ 2, 23.416 > C(t) ≥ 2

and for  0 ≤ t ≤ 0  1 ≤ B(t) ≤ 8 and for 1 < t ≤ 2, 8 > B(t) ≥ 1.5

Therefore, the curves intersect at in between (√2)/2 ≤ t ≤ 2.

8 0
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Enzo takes Vendela to see a horror movie on their first date. He knows that people who feel strong emotions rely on situational
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B) upward comparison.
C) facial feedback hypothesis.
D) Cannon-Bard theory.
c
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