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larisa86 [58]
3 years ago
10

Eighteenpassengers get on an airport shuttle at the airport. The shuttle has a route that includessixhotels, and passengersgetof

f the shuttle at theirhotel. The driver records how many passengers leave the shuttle at each hotel. How many different possibilities exist?
Mathematics
1 answer:
xz_007 [3.2K]3 years ago
5 0

Answer:

So, exist 18564 different possibilities.

Step-by-step explanation:

We know that the eighteen passengers get on an airport shuttle at the airport.  The shuttle has a route that includes six hotels, and passengers get off the shuttle at their hotel.

We calcuate how many different possibilities exist that eighteen passengers can choose six hotels. We get:

C_6^{18}=\frac{18!}{6!(18-6)!}=18564

So, exist 18564 different possibilities.

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<h2>Hello!</h2>

The answer is:

The coordinates of the midpoint are:

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<h2>Why?</h2>

We can find the midpoint of the segment with the given endpoints using the following formula.

The midpoint of a segment is given by:

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We are given the points:

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