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disa [49]
3 years ago
13

I attatched the problem

Mathematics
2 answers:
Lorico [155]3 years ago
8 0

Heya!

--------------------

Things to know before we solve:

The "6" at the top means that the the sequence only goes to the 6th term.

k = 3 represents that the sequence starts with the 3rd term.

(-2k + 5) represents the rule of the sequence, we can substitute 3, 4, 5, and 6 to solve for the terms of the sequence.

--------------------

Solving for each term:

3rd term:

-2(3) + 5

-6 + 5

-1

4th term:

-2(4) + 5

-8 + 5

-3

5th term:

-2(5) + 5

-10 + 5

-5

6th term:

-2(6) + 5

-12 + 5

-7

--------------------

Simplifying:

Write these terms in expanded form:

(-1) + (-3) + (-5) + (-7)

Find the sum of the series:

(-1) + (-3) + (-5) + (-7) = -16

--------------------

Answer:

The sum of the series is -16

--------------------

Best of Luck!

DanielleElmas [232]3 years ago
6 0

Answer:

-16

Step-by-step explanation:

k = 3

-2(3) + 5 = -1

k = 4

-2(4) + 5 = -3

k = 5

-2(5) + 5 = -5

k = 6

-2(6) + 5 = -7

(-1) + (-3) + (-5) + (-7)

= -16

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In an arithmetic series a1= -14 and a5=30 find the sum of the first 5 terms
Oxana [17]

The sum of the 5 terms in the arithmetic series is 40.

Step-by-step explanation:

Step 1;  First we need to determine the three values between a1= -14 and a5=30. The difference between the first and fifth value = 30 - (-14) = 30 + 14 = 44.

Since there are 4 values after a1 we divide the difference by the number of terms, the difference between each term = 44 / 4 = 11. So the difference between each term is 11.

Step 2; To find out the terms we just add the difference to the previous number.

a1 = -14.

a2 = -14 + 11 = -3.

a3 = -3 + 11 = 8.

a4 = 8 + 11 = 19.

a5 = 19 + 11 = 30.

So a1 + a2 + a3 + a4 + a5 = -14 -3 + 8 + 19 + 30 = 40.

5 0
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The sum of digits in a two digit number formed by two digits from 1 to 9 is 8. If 9 is added to a number then both the digits be
Arturiano [62]
<h2>Explanation:</h2><h2></h2>

Here we need to set a system of two linear equations in two variables. So:

  • <em>The sum of digits in a two digit number formed by two digits from 1 to 9 is 8:</em>

Let x \ and \ y be those digits, then:

x+y=8 \ \ldots eq1

  • <em>If 9 is added to a number then both the digits become equal. find the number:</em>

<em />

<em />10x+y+9 \ldots expression \ 1<em />

<em />

But from eq 1:

y=8-x

Substituting y into the expression 1:

10x+(8-x)+9=9x+17

The x-value will be found by hit and trial, so:

  • Let x = 1:

9x + 17 = 9(1)+17 = 26

We have to reject this solution because digits are different.

  • Let x = 2:

9x + 17 = 9(2)+17 = 35

We have to reject this solution because digits are different.

  • Let x = 3:

9x + 17 = 9(3)+17 = 44

<em>Then this is a two digit number formed by two equal digits. </em>

Finally, the number is:

44

3 0
3 years ago
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