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Alinara [238K]
3 years ago
12

Can someone help me with this?? If you can't see the picture don't bother to answer.

Mathematics
1 answer:
Georgia [21]3 years ago
7 0
J is correct. the scale is balanced, so x = 1. there are 9 1’s on the right, and 6 1’s on the left. there are 3 more blocks, and they would have to each be 1.
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Why is the vertex of vertex form y=a(x-h)^2+k (h,k) rather than (-h,k)? If that was y=2(x-5)^2+6, the vertex would be at (5,6) w
Sindrei [870]

9514 1404 393

Answer:

  (5, 6) is (h, k)

Step-by-step explanation:

Vertex form is an instance of the transformation of parent function f(x) = x². It is vertically scaled by a factor of 'a', and translated so the vertex is point (h, k). That is, the transformed vertex is h units right and k units up from that of the parent function (0, 0).

Parent:

  f(x) = x^2

Transformed:

  f(x) = a(x -h)^2 +k

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When you compare the form to your specific instance, you need to pay attention to what it is that you're comparing. As the attachment shows, ...

  • a = 2
  • -h = -5   ⇒   h = 5
  • k = 6

Hence the vertex is (h, k) = (5, 6). The second attachment shows this on a graph.

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3 years ago
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miv72 [106K]

Answer:

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Step-by-step explanation:

Just did the test

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