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3 years ago

One half of a number is 8 less than the number itself

2 answers:

6 0

The question is a little vague but I believe the answer would be 16. 16 divided in half is 8. And that is 8 less than 16. < Not the answer for this question.

I didn't understand the question until Maria answered, she is completely right! Sorry for the misunderstanding.

Vsevolod [243]3 years ago

5 0

1/2 of x is 2/3 of x minus 8

(1/2)x = (2/3)x -8

clear fraction by multiplying by 6

3x = 4x -48

x = 48

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Danny buys 4 pizzas and some pretzels for his baseball team. The cost of each pizza is $8.99, and the cost of each pretzel is $0

Luba_88 [7]

Answer:

Step-by-step explanation: The answer to your question is 15 pretzels.To figure this out, you first multiply 8.99 by 4 since he did buy 4 pizzas and each pizza is 8.99. Then once you do that, you should come up with 35.96. Then subtract 50.81 from 35.96,which should give you 14.85. Then just divide 14.85 by 0.99 to figure out the amount of pretzels he bought.It should give you 15.Hope this helps!!!!

Please give brainliest!!!☺

4 0

3 years ago

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Hi, Could anyone help me with my homework

tatiyna

Answer:

$\hookrightarrow \sf x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096$

solving steps:

$\rightarrow \sf (x + 4)^6$

$\bold{rewrite \ the \ following}$

$\rightarrow \sf (x + 4)^2 (x + 4)^2 (x + 4)^2$

$\bold {formula \ used : \sf (x+a)^2 = (x^2 + 2xa + a^2)}$

$\rightarrow \sf (x^2 + 8x+16) (x^2 + 8x+16) (x^2 + 8x+16)$

$\bold{simplify \ by \ removing \ parenthesis}$

$\rightarrow \sf (x^4 +8x^3 + 16x^2 + 8x^3 +64x^2 + 128x+16x^2+128x+256 ) (x^2 + 8x+16)$

$\bold{basic \ addition \ of \ integers }$

$\rightarrow \sf (x^4+16x^3+96x^2+256x+256) (x^2 + 8x+16)$

$\bold{remove \ parenthesis}$

$\rightarrow \sf (x^6 + 16x^5 + 96x^4 + 256x^3 + 256x^2 + 8x^6 + 128x^4 + 768x^3 + 2048x^2 + 2048 + 16x^4 + 256x^3 + 1536x^2 + 4096x + 4096)$

$\bold {final \ answer:}$

$\rightarrow \sf x^6+24x^5+240x^4+1280x^3+3840x^2+6144x+4096$

8 0

2 years ago

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gizmo_the_mogwai [7]

Answer:

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Step-by-step explanation:

4 0

3 years ago

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Factorize: (a+b)^2 + 4 (a+b)+ 4

pashok25 [27]

Factorized: (a + b + 2) ^2

3 0

3 years ago

If the following fraction is reduced, what will be the exponent on the p? - 5p^5q^4/8p^2q^2 5 4 3 2

SSSSS [86.1K]

$\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
-\cfrac{5p^5q^4}{8p^2q^2}\implies -\cfrac{5}{8}\cdot \cfrac{p^5q^4}{p^2q^2}\implies -\cfrac{5}{8}\cdot p^5p^{-2}q^4q^{-2}
\\\\\\
-\cfrac{5}{8}\cdot p^{5-2}q^{4-2}\implies -\cfrac{5\stackrel{\downarrow }{p^3}q^2}{8}$

8 0

3 years ago

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