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kogti [31]
3 years ago
5

One half of a number is 8 less than the number itself

Mathematics
2 answers:
mamaluj [8]3 years ago
6 0
The question is a little vague but I believe the answer would be 16. 16 divided in half is 8. And that is 8 less than 16. < Not the answer for this question.

I didn't understand the question until Maria answered, she is completely right! Sorry for the misunderstanding.
Vsevolod [243]3 years ago
5 0
1/2 of x is 2/3 of x minus 8

(1/2)x = (2/3)x -8

clear fraction by multiplying by 6

3x = 4x -48

x = 48
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Find the Equation of a line that has a slope of 5 and passes through ( 2, 8 ). Detailed answers would be appreciated.
Sophie [7]
Y = 5x+8<slope intercept 
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den301095 [7]

Answer:

2S + J = 24000

Step-by-step explanation:

let Susan be S

let Jinan be J

they paid 24000

susan paid twice as muh as jinan did​

2S + J = 24000

therefore equation is

2S + J = 24000

3 0
3 years ago
Ed counts 23 black cars, 9 red cars, 17 blue cars, 25 white cars and 21 silver cars during 20 minutes of watching. How many more
amid [387]
23 black cars
9 red cars
17 blue cars
25 white cars
21 silver cars

(white cars + blue cars) - (sliver cars + red cars)
(25 + 17) - (21 + 9)
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7 0
3 years ago
What is 1/4 X 5/16 equal
VashaNatasha [74]
\frac{1}{4} x \frac{5}{16}

   1 x 5 = 5 
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\frac{5}{64}  is the answer 

In simplest form the answer would be \frac{5}{64} because it cant be divided any farther.   


6 0
4 years ago
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Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 L of a dyesolution with a c
nordsb [41]

Answer:

Time,t that it will elapse before the concerntration of the dye in the tank reaches1% of its original value is 460.52 seconds

Step-by-step explanation:

Let Q(t) = amount of dye for all time,t.

Let Q'= rate in - rate out.

But Q/200 = concerntration of dye

Therefore rate out= Q/200 ×2.

Q'/Q = - 1/100

Dividing by Q gives

Ln/Q/ + c = -1/100t + c1

Integrating both sides with respect to t

Ln/Q/ = -1/100t + c2.

c1 and c1 are just another constants

Q= c3e^-t/100

Exponentiating both sides will cause the absolute values to get absorbed into the constants giving rise to a new constant c3

200= c3-0/100

c3= 200

2= 200e^-t/100

Ln1/100= - t/100

Ln0.01 = - t/ 100

Cross multiply

t= Ln0.01 × 100

t = 4.6052 ×100

t = 460.52seconds

7 0
3 years ago
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