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melamori03 [73]
4 years ago
7

Can anyone help me with this question? I’m cured taking a test and I got confused on this one question

Mathematics
1 answer:
Marysya12 [62]4 years ago
4 0
I believe the answer you want is D
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The weights of a certain type of captured fish can be described by a bell-shaped distribution (symmetric and unimodal) with a me
postnew [5]

Answer:

0.913716

Step-by-step explanation:

Given a normal distribution :

Mean, x = 1050

Standard deviation, σ = 375

The Zscore = (x - mean) / σ

Zscore = (675 - 1050) / 275

Zscore = - 1.364

The probability :

P(Z > - 1.364)

P(Z > - 1.364) = 1 - P(Z < - 1.364) = 1 - 0.086284

P(Z > - 1.364) = 0.913716

8 0
3 years ago
What is the measure of complemnt angle 42
SIZIF [17.4K]

Answer:

Complemetry angle = 90° - 40°

= 50°

5 0
2 years ago
Read 2 more answers
PLEASE HELP 13 MIN LEFT HELLPPPPP!!!!!!! I’ll mark brainliest
vekshin1

Answer:

D.

Step-by-step explanation:

4 0
3 years ago
Suppose that prices of a certain model of a new home are normally distributed with a mean of $150,000. Use the 68-95-99.7 rule t
levacccp [35]

Answer:

68% of buyers paid between $147,700 and $152,300.

Step-by-step explanation:

We are given that prices of a certain model of a new home are normally distributed with a mean of $150,000.

Use the 68-95-99.7 rule to find the percentage of buyers who paid between $147,700 and $152,300 if the standard deviation is $2300.

<u><em>Let X = prices of a certain model of a new home</em></u>

SO, X ~ Normal(\mu=150,000 ,\sigma=2,300)

The z score probability distribution for normal distribution is given by;

                             Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean price = $150,000

            \sigma = standard deviation = $2,300

<u>Now, according to 68-95-99.7 rule;</u>

Around 68% of the values in a normal distribution lies between \mu-\sigma and \mu-\sigma.

Around 95% of the values occur between \mu-2\sigma and \mu+2\sigma .

Around 99.7% of the values occur between \mu-3\sigma and \mu+3\sigma.

So, firstly we will find the z scores for both the values given;

         Z  =  \frac{X-\mu}{\sigma}  =  \frac{147,700-150,000}{2,300}  = -1

         Z  =  \frac{X-\mu}{\sigma}  =  \frac{152,300-150,000}{2,300}  = 1

This indicates that we are in the category of between \mu-\sigma and \mu-\sigma.

SO, this represents that percentage of buyers who paid between $147,700 and $152,300 is 68%.

7 0
4 years ago
A book shop offers a 24% discount on books. Sam has to pay $ if he purchases books with an original price of $84.
riadik2000 [5.3K]

Answer:

$63.84

Step-by-step explanation:

A book shop offers a discount on a book = 24%

The original price of the book = $84.00

we have to calculate 24% of $84 and then subtract the discount price in the original price.

Sam purchases this book = 84 -(24% × 84)

                                          = 84 - ( 0.24 × 84)

                                          = 84 - 20.16

                                          = $63.84

Sam has to pay $63.84 if he purchases book.

8 0
3 years ago
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