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ddd [48]
3 years ago
5

A diagonal of a square is 36 feet long. What is the area of the square?

Mathematics
1 answer:
Rzqust [24]3 years ago
3 0
So you can you the Pythagorean theorem to solve this problem.

if each side of the square is a certain length x, then the square is made up of two right triangles.

the sides adjacent to the right angle are length x while the hypoteneus is the diagonal whcih measures 36 feet.

a^2 + b^2 = c^2

x^2 + x^2 = 36^2

2x^2 = 1296

x^2 = 648

x = 25.456

area of a square = x^2 = 648 ft^2
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Imagine a pond. In it sits one lilypad, which reproduces once a day. Each of its offspring also reproduces once a day, doubling
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Step-by-step explanation:

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4 0
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901334 x 2368 = ? I WILL GIVE BRAINLIEST TO A CORRECT ANSWER PLEASE HURRY
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Answer:

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Step-by-step explanation:

I hope this helps you :)

5 0
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A packaging company is planning is in the planning stages of creating a box that include a three dimensional support inside the
Oliga [24]

Answer:

The length of the diagonal support is 69 feet.

Step-by-step explanation:

Dimensions of the box: length = 6 feet

                                       width = 5 feet

                                       height = 8 feet

The diagonal support relates with the diagonal of the base and the height.

From the base of the box, let the length of its diagonal be represented by x. Applying Pythagoras theorem;

/Hyp/^{2} = /Adj 1/^{2} + /Adj 2/^{2}

x^{2} = 6^{2} + 5^{2}

x^{2} = 36 + 25

   = 61

x = \sqrt{61}

  = 7.81

let the length of the diagonal support be represented by l. So that;

/Hyp/^{2} = /Adj 1/^{2} + /Adj 2/^{2}

l^{2} = x^{2} + 8^{2}

  = \sqrt{61} + 64

l  = \sqrt{\sqrt{61} + 64 }

  = 61 + 8

  = 69

Thus, the length of the diagonal support is 69 feet.

6 0
3 years ago
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