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Kisachek [45]
4 years ago
6

victor has the map scale missing.he knows the distance from the lake to the youth center is 8 miles. on the map they are 2in. ap

art. what is the scale for victors map
Mathematics
2 answers:
kupik [55]4 years ago
6 0
The <u>correct scale</u> is 1 in = 4 mi.

<u>Explanation</u>:

The scale tells us what a given measurement on the map equals in real-life distance.  

The measurement on the map that we have is 2 inches, and it equals 8 miles:

2 in = 8 mi

This can also be written as 2/8.  This fraction can be simplified, since both 2 and 8 are divisible by 2; it will simplify to 1/4.  This is the same as 
1 in = 4 mi.
Cerrena [4.2K]4 years ago
5 0

Answer:

The correct scale is 1 inch = 4 miles.

Step-by-step explanation:

Map scale is defined as the ratio between the marked distance on a map to  the corresponding distance on the ground.

Here, it is given that the measurement on the map is 2 inches, and it equals to 8 miles; so 2 inches = 8 miles

Simplifying this we get:

1 inch = 4 miles.

Hence, the scale is 1 inch equals 4 miles.

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Step-by-step explanation:

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Somebody please help me on this?! What is the correct postulate or theorem for this one..
IRINA_888 [86]

Answer:

Segment Addition Postulate

Step-by-step explanation:

In geometry, the Segment Addition Postulate states that given 2 points A and C(in this case S and O), a third point B(in this case R) lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

Meaning for R to lie on the line SO;

SR + RO must be equal to SO

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Need with this problem please.
astraxan [27]

Answer:

It would be 3/4 which is the fractional version of 0.75

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5 0
3 years ago
Use the augmented matrix method to solve the following system of equations. Your answers may be given as decimals or fractions.
Alexandra [31]

Answer:

x\ =\ \dfrac{21}{5}

y\ =\ \dfrac{3}{5}

z = 2

Step-by-step explanation:

Given equations are

x - 2y - z = 2

x + 3y - 2z = 4

-x + 2y + 3z = 2

from the given equations the augmented matrix can be written as

\left[\begin{array}{ccc}1&-2&-1:2\\1&3&-2:4\\-1&2&3:2\end{array}\right]

R_2=>R_2-R_1\ and\ R_3=>R_3+R_1

=\ \left[\begin{array}{ccc}1&-2&-1:2\\0&5&-1:2\\0&0&2:4\end{array}\right]

R_2=>\dfrac{R_2}{5}

=\ \left[\begin{array}{ccc}1&-2&-1:2\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\0&0&2:4\end{array}\right]

R_1=>R_1+2.R_2

=\ \left[\begin{array}{ccc}1&0&-1-\dfrac{2}{5}:2+\dfrac{4}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&2:4\end{array}\right]

=\ \left[\begin{array}{ccc}1&0&\dfrac{-7}{5}:\dfrac{14}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&2:4\end{array}\right]

R_3=>\dfrac{R_3}{2}

=\ \left[\begin{array}{ccc}1&0&\dfrac{-7}{5}:\dfrac{14}{5}\\\\0&1&\dfrac{-1}{5}:\dfrac{2}{5}\\\\0&0&1:2\end{array}\right]

R_1=>R_1+\dfrac{7}{5}R_3\ and\ R_2+\dfrac{1}{5}R_3

=\ \left[\begin{array}{ccc}1&0&0:\dfrac{14}{5}+\dfrac{7}{5}\\\\0&1&0:\dfrac{2}{5}+\dfrac{1}{5}\\\\0&0&1:2\end{array}\right]

So, from the above augmented matrix, we can write

x\ =\ \dfrac{21}{5}

y\ =\ \dfrac{3}{5}

z = 2

7 0
3 years ago
1/3(x+4)=20 need help
sukhopar [10]


1/3(x+4)=20

1/3x+4/3=20

1/3x=56/3

x= (56/3) / (1/3)

x= 56

5 0
3 years ago
Read 2 more answers
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