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8090 [49]
2 years ago
11

100-point Question!!!

Mathematics
1 answer:
FrozenT [24]2 years ago
4 0

Answer:

Two or more independent functions (say f(x) and g(x)) can be combined to generate a new function (say g(x)) using any of the following approach.

h(x) = f(x) + g(x)h(x)=f(x)+g(x) h(x) = f(x) - g(x)h(x)=f(x)−g(x)

h(x) = \frac{f(x)}{g(x)}h(x)=

g(x)

f(x)

h(x) = f(g(x))h(x)=f(g(x))

And many more.

The approach or formula to use depends on the question.

In this case, the combined function is:

f(x) = 75+ 10xf(x)=75+10x

The savings function is given as

s(x) = 85s(x)=85

The allowance function is given as:

a(x) = 10(x - 1)a(x)=10(x−1)

The new function that combined his savings and his allowances is calculated as:

f(x) = s(x) + a(x)f(x)=s(x)+a(x)

Substitute values for s(x) and a(x)

f(x) = 85 + 10(x - 1)f(x)=85+10(x−1)

Open bracket

f(x) = 85 + 10x - 10f(x)=85+10x−10

Collect like terms

mark as brainiest

f(x) = 85 - 10+ 10xf(x)=85−10+10x

f(x) = 75+ 10xf(x)=75+10x

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Mr.Williams physical education class lasts 7/8 hour if instruciton is 1/5 how many minutes are not spent on instruction?
g100num [7]
= 7/8 − 1/5

= ((7 × 5) − (1 × 8)) / (8 × 5)

= (35 - 8) / 40

= 27/40


SO, 27/40 minutes are NOT spend on instructions.
Hope I was able to help! :)
6 0
3 years ago
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Law of reflection. Easy question please help (picture included)
PIT_PIT [208]
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6 0
3 years ago
Suppose you walk down a school hallway at a rate of 5 ft/s, and you reach your destination in 20 seconds. How do you write a fun
8090 [49]

Answer:

Step-by-step explanation:

Let's write a equation.

5 ft = 20 seconds

(five feet is reachable in 20 seconds)

Divide both sides by 5.

5/5=1

20/5=4

1 ft = 4 seconds

Let's say the destination is d and f is foot.

d = 4f

7 0
3 years ago
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The total number of people at a football game was 5600. Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
rewona [7]

Answer:

1100 field-side tickets and 4500 end-zone tickets.

Step-by-step explanation:

Let x represent number of field side tickets and y represent number of end-zone tickets.

We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

x+y=5600...(1)

y=5600-x...(1)    

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.

Cost of x field side tickets would be 40x and cost of y end-zone tickets would be 20y.

The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

40x+20y=134000...(2)

Upon substituting equation (1) in equation (2), we will get:

40x+20(5600-x)=134000

40x+112000-20x=134000

20x+112000=134000

20x+112000-112000=134000-112000

20x=22000

\frac{20x}{20}=\frac{22000}{20}

x=1100

Therefore, 1100 field side tickets were sold.

Upon substituting x=1100 in equation (1), we will get:

y=5600-1100

y=4500

Therefore, 4500 end-zone tickets were sold.

3 0
3 years ago
Divide 1/3 yd by 9/13 ? please show work
babunello [35]

Answer:

13/27

Step-by-step explanation:

1/3 ÷ 9/13

Copy dot flip

1/3 * 13/9

13/27

5 0
3 years ago
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