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AlexFokin [52]
3 years ago
7

Shade in some or all of the grids to show that 2 ones is the same as 20 tenths

Mathematics
1 answer:
scZoUnD [109]3 years ago
4 0
Given three grids with each grid representing one whole.
Each grid represents 1 ones and each vertical bar of a grid represent 1 tenth.
There are 10 vertical bars in each grid, hence each grid represent 1 ones = 10 tenths and 2 grids represent 2 ones = 20 tenths.

Therefore, two complete grids are to be shaded to <span>show that 2 ones is the same as 20 tenths</span>
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I need help asap please.
Brilliant_brown [7]

Answer:

an exponential equation has the form y=ar^x where y=final amount, a=initial amount, r=rate, and x=time, in this case

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Step-by-step explanation:

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3 years ago
The qoutient of any two nonzero integers is an integer. True or false
guapka [62]
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Here is a counterexample.

3/4= 0.75

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8 0
3 years ago
Explain how use mental math in 17+38
asambeis [7]
You would first look at the tens place numbers; 10 and 30. and add them together making 40. after that you'd take the ones places and add them together; 7 and 8. add those together and you'd get 15. to finish you just need to add the two numbers together 40 and 15.
7 0
3 years ago
Write a quadratic equation in the form x² + bx+c=0 that has the following
vfiekz [6]

Answer:

x^2-6x+5

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7 0
3 years ago
Solve for n: c= 6n−5g /11t
qwelly [4]

Answer: \frac{11tc+5g}{66t}=n

Step-by-step explanation:

You have the equation c=6n-\frac{5g}{11t}.

Then, to solve for the variable n from the equation you need:

Make the subtraction of the right side of the equation:

(As the denominators are 1 and 11t, the least common denominator is 11t)

c=\frac{(6n)(11t)-5g}{11t}\\\\c=\frac{66nt-5g}{11t}

Multiply  11t to both sides:

(11t)c=(\frac{66nt-5g}{11t})(11t)\\\\11tc=66nt-5g

Add 5g to both sides:

11tc+5g=66nt-5g+5g\\\\11tc+5g=66nt

And finally divide both sides by 66t:

\frac{11tc+5g}{66t}=\frac{66nt}{66t}\\\\\frac{11tc+5g}{66t}=n

3 0
3 years ago
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