All categories

2 years ago

Plz open this power point and help me

Mathematics

1 answer:

insens350 [35]2 years ago

3 0

ANSWER: Company C

EXPLANATION:

1) Find the least common multiple of 6, 10 and 12. This would be 60 because:

6 x 10 = 60

10 x 6 = 60

12 x 5 = 60

2) Now you can figure out how much money each company gives for every $60 worth of gift wrap by multiplying the amount they gave in the paragraph by the same as what you did in the calculations above.

Company A

$1 x 10 = $10 for every $60 worth of gift wrap sold

Company B

$2 x 6 = $12 for every $60 worth of gift wrap sold

Company C

$3 x 5 = $15 for every $60 worth of gift wrap sold

ARGUMENT

Company C should be selected because they give the most money per dollar ($15 per $60 worth of gift wrap sold).

You might be interested in

Simplify u^2+3u/u^2-9 A.u/u-3, =/ -3, and u=/3 B. u/u-3, u=/-3

VashaNatasha [74]

  The correct answer is: Answer choice: [A]:
__________________________________________________________
→  " $\frac{u}{u-3}$ " ; " { u $\neq$ ± 3 } " ;

  →  or, write as: " u / (u − 3) " ;  {" u ≠ 3 "}  AND: {" u ≠ -3 "} ;
__________________________________________________________
Explanation:
__________________________________________________________
We are asked to simplify:

   $\frac{(u^2+3u)}{(u^2-9)}$ ;

Note that the "numerator" —which is: "(u² + 3u)" — can be factored into:
  → " u(u + 3) " ;

And that the "denominator" —which is: "(u² − 9)" — can be factored into:
  → "(u − 3) (u + 3)" ;
___________________________________________________________
Let us rewrite as:
___________________________________________________________

→ $\frac{u(u+3)}{(u-3)(u+3)}$ ;

___________________________________________________________

→ We can simplify by "canceling out" BOTH the "(u + 3)" values; in BOTH the "numerator" AND the "denominator" ;  since:

" $\frac{(u+3)}{(u+3)} = 1$ " ;

→ And we have:
_________________________________________________________

→  " $\frac{u}{u-3}$ " ; that is: " u / (u − 3) " ; { u $\neq 3$ } .
and: { u $\neq-3$ } .

→ which is:  "Answer choice: [A] " .
_________________________________________________________

NOTE:  The "denominator" cannot equal "0" ; since one cannot "divide by "0" ;

and if the denominator is "(u − 3)" ; the denominator equals "0" when "u = -3" ; as such:

"u $\neq$ 3" ;

→ Note: To solve: "u + 3 = 0" ;

Subtract "3" from each side of the equation;

→ " u + 3 − 3 = 0 − 3 " ;

→ u = -3 (when the "denominator" equals "0") ;

→ As such: " u $\neq$ -3 " ;

Furthermore, consider the initial (unsimplified) given expression:

→   $\frac{(u^2+3u)}{(u^2-9)}$ ;

Note:  The denominator is: "(u²  − 9)" .

The "denominator" cannot be "0" ; because one cannot "divide" by "0" ;

As such, solve for values of "u" when the "denominator" equals "0" ; that is:
_______________________________________________________

→ " u² − 9 = 0 " ;

→ Add "9" to each side of the equation ;

→ u² − 9 + 9 = 0 + 9 ;

→ u² = 9 ;

Take the square root of each side of the equation;
to isolate "u" on one side of the equation; & to solve for ALL VALUES of "u" ;

→ √(u²) = √9 ;

→ | u | = 3 ;

→ " u = 3" ; AND; "u = -3 " ;

We already have: "u = -3" (a value at which the "denominator equals "0") ;

We now have "u = 3" ; as a value at which the "denominator equals "0");

→ As such: " u $\neq 3$ " ; "u $\neq$ -3 " ;

or, write as: " { u $\neq$ ± 3 } " .

_________________________________________________________

6 0

3 years ago

For all values of x

Yuliya22 [10]

Answer:

A.) gf(x) = 3x^2 + 12x + 9

B.) g'(x) = 2

Step-by-step explanation:

A.) The two given functions are:

f(x) = (x + 2)^2 and g(x) = 3(x - 1)

Open the bracket of the two functions

f(x) = (x + 2)^2

f(x) = x^2 + 2x + 2x + 4

f(x) = x^2 + 4x + 4

and

g(x) = 3(x - 1)

g(x) = 3x - 3

To find gf(x), substitute f(x) for x in g(x)

gf(x) = 3( x^2 + 4x + 4 ) - 3

gf(x) = 3x^2 + 12x + 12 - 3

gf(x) = 3x^2 + 12x + 9

Where

a = 3, b = 12, c = 9

B.) To find g '(12), you must first find the inverse function of g(x) that is g'(x)

To find g'(x), let g(x) be equal to y. Then, interchange y and x for each other and make y the subject of formula

Y = 3x + 3

X = 3y + 3

Make y the subject of formula

3y = x - 3

Y = x/3 - 3/3

Y = x/3 - 1

Therefore, g'(x) = x/3 - 1

For g'(12), substitute 12 for x in g' (x)

g'(x) = 12/4 - 1

g'(x) = 3 - 1

g'(x) = 2.

5 0

2 years ago

What is the value of (16^3/2)^1/2

Alika [10]

Answer: =1024. *The answer must be have positive sign.*

Step-by-step explanation:

This question's it's about the order of operations. p-parenthesis, e-exponents, m-multiply, d-divide, a-add, and s-subtract. It can also go left to right.

do exponents first.

16³/2=4098=2048¹/2

2048¹=2048

2048/2

divide left to right.

2048/2=1024

Hope this helps!

Thanks!

Have a great day!

4 0

3 years ago

Please help me find f(x+h)

Kay [80]

Answer:

f(x) = -2x+5

f(x+h) = -2x -2h +5

g(x) = -4x-2

g(x+h) = -4x -4h -2

h(x) = 4x^2+1

h(x+h) = 4(x+h)^2 +1 = 4x^2 +8xh + 4h^2 +1

Q(x) = -3x^2 +4

Q(x+h) = -3(x+h)^2 +4 = -3x^2 -3h^2 -6xh + 4

3 0

2 years ago

Eric bought apples and oranges for $7.75. He paid $2.35 for all the apples

Kruka [31]

Answer:

He bought 12 oranges.

Step-by-step explanation:

Key words: "ALL the apples" "EACH orange."

7.75-2.35= 5.4

5.4/0.45= 12

8 0

3 years ago