HELP ME MATH ILL GIVE YOU BRAINLIEST

Mathematics

1 answer:

s344n2d4d5 [400]3 years ago

8 0

Answer:

zeros: x = -3, -1, +2.
end behavior: as x approaches -∞, f(x) approaches -∞.

Step-by-step explanation:

I like to use a graphing calculator for finding the zeros of higher order polynomials. The attachment shows them to be at x = -3, -1, +2.

The zeros can also be found by trial and error, trying the choices offered by the rational root theorem: ±1, ±2, ±3, ±6. It is easiest to try ±1. Doing so shows that -1 is a root, and the residual quadratic is ...

x² +x -6

which factors as (x -2)(x +3), so telling you the remaining roots are -3 and +2.

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For any odd-degree polynomial with a positive leading coefficient, the sign of the function will match the sign of x when the magnitude of x gets large. Thus as x approaches negative infinity, so does f(x).

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A firm maintains 22 cars for business purposes. From past experience, it is known that approximately 10% will require major engi

seropon [69]

Answer:

The probability that at most 1 car will require major engine repair next year is P=0.3392.

Step-by-step explanation:

This can be modeled as a binomial random variable, with n=22 and p=0.1.

The probability that exavtly k cars will require major engine repair next year is:

$P(x=k) = \dbinom{n}{k} p^{k}(1-p)^{n-k}$

Then, the probability that at most 1 car will require major engine repair next year is:

$P(x\leq1)=P(x=0)+P(x=1)\\\\\\P(x=0) = \dbinom{22}{0} p^{0}(1-p)^{22}=1*1*0.0985=0.0985\\\\\\P(x=1) = \dbinom{22}{1} p^{1}(1-p)^{21}=22*0.1*0.1094=0.2407\\\\\\P(x\leq1)=0.0985+0.2407\\\\P(x\leq1)=0.3392$