Answer:
1/5
Step-by-step explanation:
We assume the events are independent, so the probability of the joint event is the product of the probabilities of the individual events.
P(Y or W) = 2 letters of 5 = 2/5
P(easy) = 1 of 2 kinds = 1/2
The product of these is ...
P((Y or W) and (easy)) = (2/5)(1/2) = 1/5
_____
In both cases, we have to assume that each of the possible outcomes is equally likely.
Answer:
2nd Graph
Step-by-step explanation:
200$ because if you do 2000dovided by 10 then it will equal=200 so loook 200x10=2000 so 1/10=200
Since there are 6 students out of which one needs to be selected, the principal chose two die on which there are six numbers each numbered from 1 , 2, 3, 4, 5, 6.
Since there are two dice, the total possible outcome is 36.
Hence, the probability of getting one number each is 1/36
Hence, the principal used a fair method because each result is an equally likely possible outcome.
Option B is correct.
