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3 years ago

5 m3 m6m8mwhat is the S.A.?

Mathematics

1 answer:

Sergio [31]3 years ago

8 0

Answer:

Step-by-step explanation:

i am not sure

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Find the value of xxx in the isosceles triangle shown below.

MAXImum [283]

Answer:

X = 10

Step-by-step explanation:

if we say 1/2 base = <em>a</em>

a² = 13² - 12²

a² = 25

a = √25

a = 5

if 1/2 base = 5 then x = a × 2

hence X = 5 × 2 = 10

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2 years ago

Jean noticed that the tar pit bubbled more on warm days than on cool days or at night. Is the air temperature the dependent vari

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2 years ago

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2 years ago

What is the number in the middle of 1.5 and7.1

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3 years ago

Read 2 more answers

Six different second-year medical students at Bellevue Hospital measured the blood pressure of the same person. The systolic re

Yanka [14]

Answer:

$Range=14$

$\sigma^2 =32.4$

$\sigma = 5 .7$

The standard deviation will remain unchanged.

Step-by-step explanation:

Given

$Data: 136, 129, 141, 139, 138, 127$

Solving (a): The range

This is calculated as:

$Range = Highest - Least$

Where:

$Highest = 141; Least = 127$

So:

$Range=141-127$

$Range=14$

Solving (b): The variance

First, we calculate the mean

$\bar x = \frac{1}{n} \sum x$

$\bar x = \frac{1}{6} (136+ 129+ 141+ 139+ 138+ 127)$

$\bar x = \frac{1}{6} *810$

$\bar x = 135$

The variance is calculated as:

$\sigma^2 =\frac{1}{n-1}\sum(x - \bar x)^2$

So, we have:

$\sigma^2 =\frac{1}{6-1}*[(136 - 135)^2 +(129 - 135)^2 +(141 - 135)^2 +(139 - 135)^2 +(138 - 135)^2 +(127 - 135)^2]$

$\sigma^2 =\frac{1}{5}*[162]$

$\sigma^2 =32.4$

Solving (c): The standard deviation

This is calculated as:

$\sigma = \sqrt {\sigma^2 }$

$\sigma = \sqrt {32.4}$

$\sigma = 5 .7$ --- approximately

Solving (d): With the stated condition, the standard deviation will remain unchanged.

5 0

2 years ago

5 m3 m6m8mwhat is the S.A.?​

5 m3 m6m8mwhat is the S.A.?