Answer:
60 more gallons
Step-by-step explanation:
Answer:
Option d - 204 m
Step-by-step explanation:
Given : The atmospheric pressures at the top and the bottom of a building are read by a barometer to be 96.0 and 98.0 kPa. If the density of air is 1.0 kg/m³.
To find : The height of the building ?
Solution :
We have given atmospheric pressures,
![P_{\text{top}}=96\ kPa](https://tex.z-dn.net/?f=P_%7B%5Ctext%7Btop%7D%7D%3D96%5C%20kPa)
![P_{\text{bottom}}=98\ kPa](https://tex.z-dn.net/?f=P_%7B%5Ctext%7Bbottom%7D%7D%3D98%5C%20kPa)
The density of air is 1.0 kg/m³ i.e. ![\rho_a=1\ kg/m^3](https://tex.z-dn.net/?f=%5Crho_a%3D1%5C%20kg%2Fm%5E3)
Atmospheric pressure reduces with altitude,
The height of the building is given by formula,
![H=\frac{\triangle P}{\rho_a\times g}](https://tex.z-dn.net/?f=H%3D%5Cfrac%7B%5Ctriangle%20P%7D%7B%5Crho_a%5Ctimes%20g%7D)
![H=\frac{P_{\text{bottom}}-P_{\text{top}}}{\rho_a\times g}](https://tex.z-dn.net/?f=H%3D%5Cfrac%7BP_%7B%5Ctext%7Bbottom%7D%7D-P_%7B%5Ctext%7Btop%7D%7D%7D%7B%5Crho_a%5Ctimes%20g%7D)
![H=\frac{(98-96)\times 10^3}{1\times 9.8}](https://tex.z-dn.net/?f=H%3D%5Cfrac%7B%2898-96%29%5Ctimes%2010%5E3%7D%7B1%5Ctimes%209.8%7D)
![H=\frac{2000}{9.8}](https://tex.z-dn.net/?f=H%3D%5Cfrac%7B2000%7D%7B9.8%7D)
![H=204\ m](https://tex.z-dn.net/?f=H%3D204%5C%20m)
Therefore, Option d is correct.
The height of the building is 204 meter.
Answer:
Y=4/5
Step-by-step explanation:
To find out how many inches were gained, solve it with the expression 8 - x.