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2 years ago

11

Twenty people each had 36 carrots. How many carrots are there altogether?

1 answer:

elena-s [515]2 years ago

7 0

You know that there are 25 people and each person had 36 carrots. To find how many carrots everyone has in total, you have to multiply 25 by 36.

25 times 36 is 900.

There are 900 carrots altogether.

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Solve the equation and check your solution. (If there is no solution, enter NO SOLUTION.) (4x − 6) divided by (4x+3) = 2/3

iren [92.7K]

$\frac{4x-6}{4x+3} = \frac{2}{3} \\ \\ 3(4x-6) = 2(4x+3) \\ \\ 12x - 18 = 8x +6 \\ \\ 4x = 24 \\ \\ x = 6$

8 0

2 years ago

I need help with this, it's due in 15 mins-

LiRa [457]

Answer:

Mean: 3.5263157894737

Median: 3

Mode: 3

Step-by-step explanation: The mode is 3 because the mode is for which number pops up the most, which is 3.

I got the median by crossing out 8 from the left and the right of the number set and got 3 as the last number.

I got the mean by adding up all the numbers and divided it by the amount of numbers in the set.

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2 years ago

A craftsman can sell 10 jewelry sets for $500 each. He knows

liraira [26]

Answer:15

Step-by-step explanation:

Given

Craftsman sell 10 Jewelry set for $500 each

For each additional set he will decrease the price by $ 25

Suppose he sells n set over 10 set

Earning $=\text{Price of each set}\times \text{no of set}$

Earning $=(500-25n)(10+n)$

$E=5000+500n-25n^2-250n$

differentiate to get the maximum value

$\frac{dE}{dn}=-50n+250$

Equate $\frac{dE}{dn}$ to get maximum value

$-50n+250=0$

$n=\frac{250}{50}$

$n=5$

Thus must sell 5 extra set to maximize its earnings.

5 0

2 years ago

PROPIEDADES DE LA SUMA Y PRUBA DE LA RESTA.

olga2289 [7]

Answer is c la diferencia Ed la Miya’s question el minuendo

3 0

2 years ago

The price of a cycle is reduced by 25 per cent. The new price is reduced by a further 20 per cent.Find the single reduction the

Evgen [1.6K]

Answer:

40% . The single reduction together is 40%.

Step-by-step explanation:

Let the bicycle cost is x before reduced price.

First 25% is reduced and again 20% further reduced.

Let the single reduction is y% if the two reduction together are equal.

Solution,

Case .1

reduction cost $=x\times 25%$ %

$=x\times 25/100$

$=x/4$

The cost of bicycle after reduction of 25% is

$=x-x/4=3x/4$

cost of reduction further reduction of 20% $=3x/4\times 20$ %

$=3x\times 20/(4\times 100)$

$=3x/20$

The new cost of bicycle is further reduction of 20% is

$=3x/4-3x/20$

$=\left ( 15x-3x \right )/20$

$=12x/20=3x/5$

Case.2

if single reduction is done new cost of cycle is equal

$x-x\times y$ %= $3x/5$

$x\left ( 1-y/100 \right )=3x/5$

$\left ( 100-y \right )/100=3/5$

$100-y=60$

$y=40$ %

single reduction of a cycle is 40%

8 0

2 years ago