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vagabundo [1.1K]
3 years ago
6

PLEASE HELP ASAP!!!!!!

Mathematics
1 answer:
Natali5045456 [20]3 years ago
8 0

Answer:

13.60 See the note below.

Step-by-step explanation:

Remark

This is just the reverse of the question you just did. This time you are trying to solve for c

Givens

  • a = 8
  • b = 11
  • c = ??

Solution

c^2 = a^2 + b^2        Substitute the givens.

c^2 = 8^2 + 11^2       Expand

c^2 = 64 + 121           Combine the right side by adding

c^2 = 185                   Take the square root of both sides.

sqrt(c^2) = sqrt(185)       Complete the operation

c =  13.601                   Round to the nearest 1/100 th

c = 13.60                      Note: the zero must be there or the answer does not show the nearest 1/100 th

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Label the given points as follows:
A (0, 5)
B (2, 2)
C (3, 1)
D (4, -1)

The straight line has a constant slope. Therefore it should have the same value when any two of the four points are used to calculate the slope.

Try A and B:
Slope = (2 - 5)/(2 - 0) = -3/2

Try A and C:
Slope = (1 - 5)/(3 - 0) = -4/3

Try A and D.
Slope = (-1 - 5)/(4 - 0) = -3/2

Try B and D.
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Clearly, C does not lie on the straight line.

Answer:  The point that the graph does not pass through is (3,1). 
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1 year ago
What is the value ofx in the equation 2(6x+4)-6+2x=3(4x+3) + 1<br> 1<br> 3<br> 4<br> 6
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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Equality Properties
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Step-by-step explanation:

<u>Step 1: Define Equation</u>

2(6x + 4) - 6 + 2x = 3(4x + 3) + 1

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute:                                   12x + 8 - 6 + 2x = 12x + 9 + 1
  2. Combine like terms:                   14x + 2 = 12x + 10
  3. Subtract 12x on both sides:       2x + 2 = 10
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  5. Divide 2 on both sides:              x = 4
8 0
3 years ago
Write the equation for the hyperbola with foci (–12, 6), (6, 6) and vertices (–10, 6), (4, 6).
fomenos

Answer:

\frac{(x--3)^2}{49} -\frac{(y-6)^2}{32}=1

Step-by-step explanation:

The standard equation of a horizontal hyperbola with center (h,k) is

\frac{(x-h)^2}{a^2}-\frac{(y-k)^2}{b^2}=1

The given hyperbola has vertices at (–10, 6) and (4, 6).

The length of its major axis is 2a=|4--10|.

\implies 2a=|14|

\implies 2a=14

\implies a=7

The center is the midpoint of the vertices (–10, 6) and (4, 6).

The center is (\frac{-10+4}{2},\frac{6+6}{2}=(-3,6)

We need to use the relation a^2+b^2=c^2 to find b^2.

The c-value is the distance from the center (-3,6) to one of the foci (6,6)

c=|6--3|=9

\implies 7^2+b^2=9^2

\implies b^2=9^2-7^2

\implies b^2=81-49

\implies b^2=32

We substitute these values into the standard equation of the hyperbola to obtain:

\frac{(x--3)^2}{7^2} - \frac{(y-6)^2}{32}=1

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I hope this helps you

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