Label the given points as follows:
A (0, 5)
B (2, 2)
C (3, 1)
D (4, -1)
The straight line has a constant slope. Therefore it should have the same value when any two of the four points are used to calculate the slope.
Try A and B:
Slope = (2 - 5)/(2 - 0) = -3/2
Try A and C:
Slope = (1 - 5)/(3 - 0) = -4/3
Try A and D.
Slope = (-1 - 5)/(4 - 0) = -3/2
Try B and D.
Slope = (-1 - 2)/(4 - 2) = -3/2
Clearly, C does not lie on the straight line.
Answer: The point that the graph does not pass through is (3,1).
Assuming the 2,6,1 are length, width and height we can use the formula Volume= length • width • height. When you plug those in you will get 2•6•1= 12. The volume is 12 cubic millimeters. Or 12 cubed
Answer:
x = 4
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
- Equality Properties
- Combining Like Terms
Step-by-step explanation:
<u>Step 1: Define Equation</u>
2(6x + 4) - 6 + 2x = 3(4x + 3) + 1
<u>Step 2: Solve for </u><em><u>x</u></em>
- Distribute: 12x + 8 - 6 + 2x = 12x + 9 + 1
- Combine like terms: 14x + 2 = 12x + 10
- Subtract 12x on both sides: 2x + 2 = 10
- Subtract 2 on both sides: 2x = 8
- Divide 2 on both sides: x = 4
Answer:

Step-by-step explanation:
The standard equation of a horizontal hyperbola with center (h,k) is

The given hyperbola has vertices at (–10, 6) and (4, 6).
The length of its major axis is
.



The center is the midpoint of the vertices (–10, 6) and (4, 6).
The center is 
We need to use the relation
to find
.
The c-value is the distance from the center (-3,6) to one of the foci (6,6)





We substitute these values into the standard equation of the hyperbola to obtain:

