All categories

3 years ago

What is the equation for m is between -2 and 5

Mathematics

1 answer:

Hatshy [7]3 years ago

8 0

3 is my guess, tricky question tough?

You might be interested in

Helpp i am really bad with math

Brut [27]

Answer:

1. 4y-12

2. c

For #1 you distribute the 4 to the y and the 3. 4 times 3 equals 12.

For #2 you factor out the 3 and you get 3(5x+1)

7 0

2 years ago

Read 2 more answers

PLEASE HELP ME ILL GIVE BRAINLIEST SELECT ALL THAT APLY!!!!!!!!!!!!!!!!!!!!!!!

fenix001 [56]

$y\cdot \:2\frac{1}{2} =$ $2\frac{1}{2}=\frac{2\cdot 2+1}{2}=\frac{5}{2}$ $=\frac{5y}{2}$

a) $2y+\frac{1}{2}=\frac{4y+1}{2}$

b) $2y+\frac{1}{2}y=\frac{5y}{2}$

<h3><em>So b) is the expression that is equivallent.</em></h3><h3><em></em></h3><h3><em></em></h3><h3><em>Hope I helped you!</em></h3><h3><em>Success!</em></h3>

8 0

2 years ago

Ronnie wants to buya computer table that measures 10 feet by 17 feet.The cost of the table is $16 per square foot.How much will

Black_prince [1.1K]

It will cost her 1,710 dollars because 10 times 17 is 170 and 170 times 16 is $1,710

8 0

2 years ago

There are approximately 3.2

gladu [14]

So, using the number 3,200,000 deaths per year, you want to divide it until it reaches deaths per minute.
3,200,000 divided by 365 (for days)
8767.123 divided by 24 (for hours)
365.297 divided by 60 (for minutes)
and so you get
6.088 deaths per minute

Hope this helped.

8 0

3 years ago

Use cylindrical coordinates. find the volume of the solid that lies within both the cylinder x2 y2 = 9 and the sphere x2 y2 z2 =

marissa [1.9K]

In Cartesian coordinates, the region is given by $-3\le x\le3$ , $-\sqrt{9-x^2}\le y\le\sqrt{9-x^2}$ , and $-\sqrt{16-x^2-y^2}\le z\le\sqrt{16-x^2-y^2}$ . Converting to cylindrical coordinates, using

$\begin{cases}\mathbf x(r,\theta,\zeta)=r\cos\theta\\\mathbf y(r,\theta,\zeta)=r\sin\theta\\\mathbf z(r,\theta,\zeta)=\zeta\end{cases}$

we get a Jacobian determinant of $r$ , and the region is given in cylindrical coordinates by $0\le\theta\le2\pi$ , $0\le r\le3$ , and $-\sqrt{16-r^2}\le z\le\sqrt{16-r^2}$ .

The volume is then

$\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=3}\int_{z=-\sqrt{16-r^2}}^{z=\sqrt{16-r^2}}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\dfrac{4(64-7\sqrt7)\pi}3$

6 0

2 years ago