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Mariana [72]
3 years ago
10

Two catalysts in a batch chemical process, are being compared for their effect on the output of the process reaction. A sample o

f 12 batches was prepared using catalyst 1, and a sample of 10 batches was prepared using catalyst 2. The 12 batches for which catalyst 1 was used in the reaction gave an average yield of 85 with a sample standard deviation of 4, and the 10 batches for which catalyst 2 was used gave an average yield of 81 and a sample standard deviation of 5. Find a 90% confidence interval for the difference between the population means, assuming that the populations are approximately normally distributed with equal variances.

Mathematics
1 answer:
anzhelika [568]3 years ago
3 0

Answer:

2.083 < µ1 - µ2 < 5.917  

Step-by-step explanation:

We will need to construct a 90% confidence interval for the difference of 2 means where the populations are normally distributed, and their variances are equal.

The calculations of the sample means and standard deviations are done for us.

Sample 1: Catalyst 1

n = 12, x = 85, s = 4

Sample 2:  Catalyst 2

n = 10, x = 81, s = 5

See attached photo for the construction of the confidence interval...

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I hope this helps.

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5 0
3 years ago
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professor190 [17]
Let the number be n.

Then:

n^2 + (1/n)^2 = 82/9; find n.  Find the LCD; it is 9n^2.

Mult all 3 terms by 9n^2:
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9n^4 + 9 = (82/9)(9n^2)  =>    9n^4 + 9 = ------------  
                                                                        9
Then 9n^4 - 82n^2 + 9 = 0

I used my graphing calculator to find that n = 3.  

Let's check:     is 3^2 + (1/3)^2 = 82/9?
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