Two catalysts in a batch chemical process, are being compared for their effect on the output of the process reaction. A sample o
f 12 batches was prepared using catalyst 1, and a sample of 10 batches was prepared using catalyst 2. The 12 batches for which catalyst 1 was used in the reaction gave an average yield of 85 with a sample standard deviation of 4, and the 10 batches for which catalyst 2 was used gave an average yield of 81 and a sample standard deviation of 5. Find a 90% confidence interval for the difference between the population means, assuming that the populations are approximately normally distributed with equal variances.
1 answer:
Answer:
2.083 < µ1 - µ2 < 5.917
Step-by-step explanation:
We will need to construct a 90% confidence interval for the difference of 2 means where the populations are normally distributed, and their variances are equal.
The calculations of the sample means and standard deviations are done for us.
Sample 1: Catalyst 1
n = 12, x = 85, s = 4
Sample 2: Catalyst 2
n = 10, x = 81, s = 5
See attached photo for the construction of the confidence interval...
You might be interested in
The attached graph represents the scatter plot of the table of values
<h3>How to create the scatter plot?</h3>The table of values is given as:
Variable A 1 4 2 3 5 1 3 7 6 6 2 9 7 5 8
Variable B 6 6 1 6 7 4 4 7 5 3 5 25 21 4 4
Rewrite the table as:
x 1 4 2 3 5 1 3 7 6 6 2 9 7 5 8
y 6 6 1 6 7 4 4 7 5 3 5 25 21 4 4
Next, we plot the values on a graph
See attachment for the scatter plot
Read more about scatter plot at:
#SPJ1
