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Mekhanik [1.2K]
3 years ago
6

The weight of a rock sample is measured to be 2.5 ponds. What is the percent of error in the measurement?

Mathematics
1 answer:
e-lub [12.9K]3 years ago
5 0
That makes no sense bc you can't find the percent of error without another number
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20 points for one question. You know you want to.
spayn [35]

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The answer is A.

Step-by-step explanation:

We only have to test one coordinate to find the answer. The original coordinate for N is (-1, -1). Using the formula, N' is (0, -2).

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Answer:

If she wants to face the food court, she has to turn through an angle of __225°__ anti-clockwise.

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Kiran has 10 1/2 feet of lumber and wants to make a bookshelfKiran needs two side panels that are each 5 2/3 feet. How much more
eimsori [14]

Total height of lumber, H = 10 1/2 feet = 21/2 feet .

Height of side panel, h = 5 2/3 feet = 17/3 feet .

Now,

Extra lumber required, L = 2 × Height of side panel - Total height of lumber

L=[2\times (\dfrac{17}{3})]-\dfrac{21}{2}\\\\L = \dfrac{5}{6}\ feet

Therefore, extra lumber required is \dfrac{5}{6} feet.

Hence, this is the required solution.

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−2 1/2 −5 3/4 The distance between the two numbers is
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A competitive knitter is knitting a circular place mat. The radius of the mat is given by the formula
Ilia_Sergeevich [38]

Answer: A. A'(t)=\frac{4356\pi}{(t+11)^{3}}-\frac{527076\pi}{(t+11)^{5}}

              B. A'(5) = 1.76 cm/s

Step-by-step explanation: <u>Rate</u> <u>of</u> <u>change</u> measures the slope of a curve at a certain instant, therefore, rate is the derivative.

A. Area of a circle is given by

A=\pi.r^{2}

So to find the rate of the area:

\frac{dA}{dt}=\frac{dA}{dr}.\frac{dr}{dt}

\frac{dA}{dr} =2.\pi.r

Using r(t)=3-\frac{363}{(t+11)^{2}}

\frac{dr}{dt}=\frac{726}{(t+11)^{3}}

Then

\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]

\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}

Multipying and simplifying:

\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}

The rate at which the area is increasing is given by expression A'(t)=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}.

B. At t = 5, rate is:

A'(5)=\frac{4356\pi}{(5+11)^{3}} -\frac{527076\pi}{(5+11)^{5}}

A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}

A'(5)=\frac{2408693760\pi}{4294967296}

A'(5)=1.76268

At 5 seconds, the area is expanded at a rate of 1.76 cm/s.

5 0
3 years ago
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