- The Midpoint of AB is (1,0).
Given that:
- In line AB, where the coordinates of A is (3,1) and coordinates of B is (-1,-1).
To find:
So, according the question
We know that,
The midpoint M of a line segment AB with endpoints A (x₁, y₁) and B (x₂, y₂) has the coordinates M (
).
Now from question,
We know that the the coordinates of A is (3,1) and coordinates of B is (-1,-1) of line AB.
So, we can say that
A is (3,1) or x₁ = 3 and y₁ = 1.
B (-1,-1) or x₂ = -1 and y₂ = -1.
∵ The coordinates of midpoint M (X,Y)
X = 
= 
= 2/2
X = 1.
And
Y = 
= 
= 0/2
Y = 0.
So, the midpoint of line AB is M (1,0)
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Answer:
D
Step-by-step explanation:
1/8 is tha answer............
Answer:
(x+6i)(x-6i)(x+1)
So the zeroes are 6i, -6i, -1
Step-by-step explanation:
Factor by grouping
h(x) = x^2(x+1) + 36(x+1)
h(x) = (x^2+36)(x+1)
Assuming the length is y and the width is x
Perimeter = y + y + x + x
= 2y +2x
= 2 (y + x)
if the is 8 and the perimeter is 108
108 = 2 (y +8)
108/2 = y+8
54 = y +8
54 - 8 = y
46 = y
Length = 46 inches