Answer: i have never did a math problem like this before because i'm only in the 2nd semester of 7th grade but i will try, i think it is 2090
Step-by-step explanation: 5000 divided by 2 = 2500. then you do 2500-410. 2500-410= 2090. (i hope this will help you and sorry if i did it wrong) :)
(P+T)-7 = 6. 7 less than, meaning taking away 7 from the sum of (P + T) is as much as / equal to 6
Answer:
Step-by-step explanation:
Total number of antenna is 15
Defective antenna is 3
The functional antenna is 15-3=12.
Now, if no two defectives are to be consecutive, then the spaces between the functional antennas must each contain at most one defective antenna.
So,
We line up the 13 good ones, and see where the bad one will fits in
__G __ G __ G __ G __ G __G __ G __ G __ G __ G __ G __ G __G __
Each of the places where there's a line is an available spot for one (and no more than one!) bad antenna.
Then,
There are 14 spot available for the defective and there are 3 defective, so the arrange will be combinational arrangement
ⁿCr= n!/(n-r)!r!
The number of arrangement is
14C3=14!/(14-3)!3!
14C3=14×13×12×11!/11!×3×2
14C3=14×13×12/6
14C3=364ways
Answer:
0.03125 inches 1 hour is the anwser
this also involves the conversion factor
hope this helps!!
Answer:
2458
Step-by-step explanation:
