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qwelly [4]
3 years ago
13

When solving an equation in the form by taking square roots, how many solutions will there be?

Mathematics
2 answers:
harina [27]3 years ago
6 0

Answer:

Two

Step-by-step explanation:

When you solving square equation, you will have two solutions.

Here we are given ax^2 = c

We have to solve for x.

Divide both sides by a, we get

\frac{ax^2}{a} = \frac{a}{c}

Simplifying, we get

x^2 = \frac{a}{c}

In order to find the value of x, we need to get rid of square on the left side, so we need to take the square root on both sides, we get

\sqrt{x^2} = \sqrt{\frac{a}{c} }

x = ±\sqrt{\frac{a}{c} }

So you will have a positive number and a negative number.

Therefore, there are two solutions.

ss7ja [257]3 years ago
3 0
Normally two. However, one is often extraneous. 
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The telephone company charges $1.35 fir the first 3 minutes of a phone call and $0.35 for each additional minute. i talk on the
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Answer:

$5.20

Step-by-step explanation:

Talked on the phone for 14 minutes .

14 - 3 = 11

11 x .35 = 3.85

3.85 + 1.35 = 5.2

8 0
3 years ago
Jake throws a football down the field to his teammate. Jake's hand is 5 feet above the ground when the football is released with
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2 years ago
A=zm+z solve for m please help!!!!!
Svetach [21]

Answer:

(a-z)/z = m

Step-by-step explanation:

a = zm+z

Subtract z from each side

a-z = mz+z-z

a-z = mz

Divide by z

(a-z) /z = mz/z

(a-z)/z = m

5 0
3 years ago
H(x)=1/8x^3-x^2<br><br> Over which interval does h have a positive average rate of change?
lara31 [8.8K]

Answer:

(-\infty,0)\cup(\frac{16}{3},\infty)\\That \ is x\frac{16}{3}

Step-by-step explanation:

h(x)=\frac{1}{8}x^{3} -x^{2} \\\\Differentiate \ h(x) \ with \  respect \ to \ x\\h'(x)=\frac{3}{8}x^{2} -2x

For positive rate of change h'(x)>0

\frac{3}{8} x^{2} -2x>0\\x(\frac{3}{8}x-2)>0\\\\ When \ x0 \ (multiplication \ of \ two \ positives \ is \ positive)\\\\h'(x)>0 \ when \ x\frac{16}{3} \\\\

6 0
3 years ago
What is the inverse of f(x)= cube root of x +2.
DiKsa [7]
F(x)=\sqrt[3]{x+2}
to solve for the inverse of a function you do 4 steps:
1. subsitute f(x) with y
2. switch y and x places
3. solve for y
4. subsitute y with f⁻¹(x)

so we have
f(x)=\sqrt[3]{x+2}
subsitute f(x) with y
y=\sqrt[3]{x+2}
switch x and y
x=\sqrt[3]{y+2}
solve for y

x=\sqrt[3]{y+2}
cube both sides
x^{3}=y+2
subtract 2 from both sides
x^{3}-2=y

subsitute y with f⁻¹(x)
f⁻¹(x)=x^{3}-2



the answer is f⁻¹(x)=x^{3}-2



8 0
3 years ago
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